对bash脚本函数中定义的变量使用curl POST

当我echo时，我得到这个，当我把它输入到终端时，它就会运行

curl -i \
-H "Accept: application/json" \
-H "Content-Type:application/json" \
-X POST --data '{"account":{"email":"akdgdtk@test.com","screenName":"akdgdtk","type":"NIKE","passwordSettings":{"password":"Starwars1","passwordConfirm":"Starwars1"}},"firstName":"Test","lastName":"User","middleName":"ObiWan","locale":"en_US","registrationSiteId":"520","receiveEmail":"false","dateOfBirth":"1984-12-25","mobileNumber":"9175555555","gender":"male","fuelActivationDate":"2010-10-22","postalCode":"10022","country":"US","city":"Beverton","state":"OR","bio":"This is a test user","jpFirstNameKana":"unsure","jpLastNameKana":"ofthis","height":"80","weight":"175","distanceUnit":"MILES","weightUnit":"POUNDS","heightUnit":"FT/INCHES"}' https://xxx:xxxxx@xxxx-www.xxxxx.com/xxxxx/xxxx/xxxx

但是当在bash脚本文件中运行时，我得到这个错误

curl: (6) Could not resolve host: application; nodename nor servname provided, or not known
curl: (6) Could not resolve host: is; nodename nor servname provided, or not known
curl: (6) Could not resolve host: a; nodename nor servname provided, or not known
curl: (6) Could not resolve host: test; nodename nor servname provided, or not known
curl: (3) [globbing] unmatched close brace/bracket at pos 158

这是文件中的代码

curl -i \
-H '"'Accept: application/json'"' \
-H '"'Content-Type:application/json'"' \
-X POST --data "'"'{"account":{"email":"'$email'","screenName":"'$screenName'","type":"'$theType'","passwordSettings":{"password":"'$password'","passwordConfirm":"'$password'"}},"firstName":"'$firstName'","lastName":"'$lastName'","middleName":"'$middleName'","locale":"'$locale'","registrationSiteId":"'$registrationSiteId'","receiveEmail":"'$receiveEmail'","dateOfBirth":"'$dob'","mobileNumber":"'$mobileNumber'","gender":"'$gender'","fuelActivationDate":"'$fuelActivationDate'","postalCode":"'$postalCode'","country":"'$country'","city":"'$city'","state":"'$state'","bio":"'$bio'","jpFirstNameKana":"'$jpFirstNameKana'","jpLastNameKana":"'$jpLastNameKana'","height":"'$height'","weight":"'$weight'","distanceUnit":"MILES","weightUnit":"POUNDS","heightUnit":"FT/INCHES"}'"'" "https://xxx:xxxxx@xxxx-www.xxxxx.com/xxxxx/xxxx/xxxx"

我认为我的引号有问题，但我用过很多次，也得到过类似的错误。在实际脚本中，所有变量都是用不同的函数定义的

当前回答

使用https://httpbin.org/和内联bash脚本测试的解决方案 1. 对于没有空格的变量，即1: 只需添加'之前和之后$变量替换所需字符串

for i in {1..3}; do \
  curl -X POST -H "Content-Type: application/json" -d \
    '{"number":"'$i'"}' "https://httpbin.org/post"; \
done

2. 对于带空格的输入: 用额外的“即”来包装变量。“el”:

declare -a arr=("el a" "el b" "el c"); for i in "${arr[@]}"; do \
  curl -X POST -H "Content-Type: application/json" -d \
    '{"elem":"'"$i"'"}' "https://httpbin.org/post"; \
done

哇工作:)

2017-03-30 10:52:54

其他回答

来自Athos爵士的信息非常有效!!

下面是我如何在我的curl脚本为couchDB使用它。这真的很有帮助经常出去。谢谢!

bin/curl -X PUT "db_domain_name_:5984/_config/vhosts/$1.couchdb" -d '"/'"$1"'/"' --user "admin:*****"

2014-04-07 19:54:03

乔可能会帮忙:

$ export A=this B=that C=foo D=bar
$ jo -p a=$A b=$B nested=$(jo c=$C d=$D)
{
   "a": "this",
   "b": "that",
   "nested": {
      "c": "foo",
      "d": "bar"
   }
}

2022-06-18 08:08:57

这个脚本将使用指定的JSON主体向指定的URL发送POST请求，并将服务器的响应输出到控制台:

#!/bin/bash

# Set the URL to send the request to
url='http://example.com/endpoint'

# Set the JSON body of the request
json_data='{"key1": "value1", "key2": "value2"}'

# Make the POST request with the JSON body
response=$(curl -X POST -H "Content-Type: application/json" -d "$json_data" "$url")

echo "Response from server: $response"

2022-12-20 20:00:21

几年之后，如果你使用eval或backtick替换，这可能会帮助到一些人:

postDataJson="{\"guid\":\"$guid\",\"auth_token\":\"$token\"}"

使用sed从响应的开头和结尾去掉引号

$(curl --silent -H "Content-Type: application/json" https://${target_host}/runs/get-work -d ${postDataJson} | sed -e 's/^"//' -e 's/"$//')

2018-01-17 03:42:40

以下是我从下面的回答中得到的建议:

export BASH_VARIABLE="[1,2,3]"
curl http://localhost:8080/path -d "$(cat <<EOF
{
  "name": $BASH_VARIABLE,
  "something": [
    "value1",
    "value2",
    "value3"
  ]
}
EOF
)" -H 'Content-Type: application/json'

2019-09-09 22:47:43

对bash脚本函数中定义的变量使用curl POST

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