查看bash(1)手册页中的“Array”部分,我没有找到对数组进行切片的方法。

所以我想出了这个过于复杂的函数:

#!/bin/bash

# @brief: slice a bash array
# @arg1:  output-name
# @arg2:  input-name
# @args:  seq args
# ----------------------------------------------
function slice() {
   local output=$1
   local input=$2
   shift 2
   local indexes=$(seq $*)

   local -i i
   local tmp=$(for i in $indexes 
                 do echo "$(eval echo \"\${$input[$i]}\")" 
               done)

   local IFS=$'\n'
   eval $output="( \$tmp )"
}

这样用:

$ A=( foo bar "a  b c" 42 )
$ slice B A 1 2
$ echo "${B[0]}"  # bar
$ echo "${B[1]}"  # a  b c

还有更好的办法吗?


当前回答

请参阅Bash手册页中的“参数扩展”部分。A[@]返回数组的内容,:1:2取一个长度为2的切片,从索引1开始。

A=( foo bar "a  b c" 42 )
B=("${A[@]:1:2}")
C=("${A[@]:1}")       # slice to the end of the array
echo "${B[@]}"        # bar a  b c
echo "${B[1]}"        # a  b c
echo "${C[@]}"        # bar a  b c 42
echo "${C[@]: -2:2}"  # a  b c 42 # The space before the - is necesssary

请注意,abc是一个数组元素(并且它包含一个额外的空格)这一事实被保留。

其他回答

冒着白费口舌的风险,我从@jandob的回答中受到启发,制作了这个版本

更简单(没有那么多移位逻辑或经常重写变量)。 尊重引用字符串而不处理IFS(仅限-r模式)。 允许用户通过-l标记指定[start, end]切片或[start, length]切片。 允许你回显结果数组(默认行为),或者“返回”它到一个新的数组中用于调用父数组(通过-r slicedArray)。

注意:namerefs仅在Bash >= 4.3中支持。为了支持早期版本的Bash(即Mac没有Brew的Bash),你需要使用间接方式:使用临时变量来访问数组参数,例如声明arrValuesCmd="$1[@]";declare arr=("${!arrValuesCmd}"),并使用eval作为返回值,例如eval $retArrName='("${newArr[@]}")'(注意数组声明周围的单引号)。

array.slice() {
    # array.slice [-l] [-r returnArrayName] myArray 3 5
    # Default functionality is to use second number as end index for slice (exclusive).
    # Can instead use second number as length by passing `-l` flag.
    # `echo` doesn't maintain quoted entries, so pass in `-r returnArrayName` to keep them.
    declare isLength
    declare retArrName
    declare OPTIND=1

    while getopts "lr:" opt; do
        case "$opt" in
            l)
                # If `end` is slice length instead of end index
                isLength=true
                ;;
            r)
                retArrName="$OPTARG"
                ;;
        esac
    done

    shift $(( OPTIND - 1 ))

    declare -n arr="$1"
    declare start="$2"
    declare end="$3"
    declare arrLength="${#arr[@]}"

    declare newArr=()
    declare newArrLength

    # Bash native slicing:
    #   Positive index values: ${array:start:length}
    #   Negative index values: ${array: start: length}
    # To use negative values, a space is required between `:` and the variable
    #   because `${var:-3}` actually represents a default value,
    #   e.g. `myVar=${otherVal:-7}` represents (pseudo-code) `myVar=otherVal || myVar=7`
    if [[ -z "$end" ]]; then
        # If no end is specified (regardless of `-l`/length or index), default to the rest of the array
        newArrLength="$arrLength"
    elif [[ -n "$isLength" ]]; then
        # If specifying length instead of end-index, use native bash array slicing
        newArrLength="$(( end ))"
    else
        # If specifying end-index, use custom slicing based on a range of [start, end):
        newArrLength="$(( end - start ))"
    fi

    newArr=("${arr[@]: start: newArrLength}")

    if [[ -n "$retArrName" ]]; then
        declare -n retArr="$retArrName"
        retArr=("${newArr[@]}")
    else
        echo "${newArr[@]}"
    fi
}

例子:

myArray=(x y 'a b c' z 5 14)   # length=6

array.slice myArray 2 4
# > a b c z


array.slice -l myArray 3 2
# > z 5



# Note: Output was manually quoted to show the result more clearly.
# Actual stdout content won't contain those quotes, which is
#   why the `-r returnArray` option was added.

array.slice -r slicedArray myArray -5 -3   # equivalent of [2, 4)
# > (null)
echo -e "myArray (length=${#myArray[@]}): ${myArray[@]} \nslicedArray (length=${#slicedArray[@]}): ${slicedArray[@]}"
# > myArray (length=6): x y 'a b c' z 5 14 
# > slicedArray (length=2): 'a b c' z


array.slice -lr slicedArray myArray -5 3   # length instead of index, equivalent of [2, 5)
# > (null)
echo -e "myArray (length=${#myArray[@]}): ${myArray[@]} \nslicedArray (length=${#slicedArray[@]}): ${slicedArray[@]}"
# > myArray (length=6): x y 'a b c' z 5 14 
# > slicedArray (length=3): 'a b c' z 5

请参阅Bash手册页中的“参数扩展”部分。A[@]返回数组的内容,:1:2取一个长度为2的切片,从索引1开始。

A=( foo bar "a  b c" 42 )
B=("${A[@]:1:2}")
C=("${A[@]:1}")       # slice to the end of the array
echo "${B[@]}"        # bar a  b c
echo "${B[1]}"        # a  b c
echo "${C[@]}"        # bar a  b c 42
echo "${C[@]: -2:2}"  # a  b c 42 # The space before the - is necesssary

请注意,abc是一个数组元素(并且它包含一个额外的空格)这一事实被保留。

还有一个方便的快捷方式来获取数组中以指定索引开始的所有元素。例如"${A[@]:1}"将是数组的"尾部",即没有第一个元素的数组。

version=4.7.1
A=( ${version//\./ } )
echo "${A[@]}"    # 4 7 1
B=( "${A[@]:1}" )
echo "${B[@]}"    # 7 1

像Python中的数组切片(来自rebash库):

array_slice() {
    local __doc__='
    Returns a slice of an array (similar to Python).

    From the Python documentation:
    One way to remember how slices work is to think of the indices as pointing
    between elements, with the left edge of the first character numbered 0.
    Then the right edge of the last element of an array of length n has
    index n, for example:
    ```
    +---+---+---+---+---+---+
    | 0 | 1 | 2 | 3 | 4 | 5 |
    +---+---+---+---+---+---+
    0   1   2   3   4   5   6
    -6  -5  -4  -3  -2  -1
    ```

    >>> local a=(0 1 2 3 4 5)
    >>> echo $(array.slice 1:-2 "${a[@]}")
    1 2 3
    >>> local a=(0 1 2 3 4 5)
    >>> echo $(array.slice 0:1 "${a[@]}")
    0
    >>> local a=(0 1 2 3 4 5)
    >>> [ -z "$(array.slice 1:1 "${a[@]}")" ] && echo empty
    empty
    >>> local a=(0 1 2 3 4 5)
    >>> [ -z "$(array.slice 2:1 "${a[@]}")" ] && echo empty
    empty
    >>> local a=(0 1 2 3 4 5)
    >>> [ -z "$(array.slice -2:-3 "${a[@]}")" ] && echo empty
    empty
    >>> [ -z "$(array.slice -2:-2 "${a[@]}")" ] && echo empty
    empty

    Slice indices have useful defaults; an omitted first index defaults to
    zero, an omitted second index defaults to the size of the string being
    sliced.
    >>> local a=(0 1 2 3 4 5)
    >>> # from the beginning to position 2 (excluded)
    >>> echo $(array.slice 0:2 "${a[@]}")
    >>> echo $(array.slice :2 "${a[@]}")
    0 1
    0 1

    >>> local a=(0 1 2 3 4 5)
    >>> # from position 3 (included) to the end
    >>> echo $(array.slice 3:"${#a[@]}" "${a[@]}")
    >>> echo $(array.slice 3: "${a[@]}")
    3 4 5
    3 4 5

    >>> local a=(0 1 2 3 4 5)
    >>> # from the second-last (included) to the end
    >>> echo $(array.slice -2:"${#a[@]}" "${a[@]}")
    >>> echo $(array.slice -2: "${a[@]}")
    4 5
    4 5

    >>> local a=(0 1 2 3 4 5)
    >>> echo $(array.slice -4:-2 "${a[@]}")
    2 3

    If no range is given, it works like normal array indices.
    >>> local a=(0 1 2 3 4 5)
    >>> echo $(array.slice -1 "${a[@]}")
    5
    >>> local a=(0 1 2 3 4 5)
    >>> echo $(array.slice -2 "${a[@]}")
    4
    >>> local a=(0 1 2 3 4 5)
    >>> echo $(array.slice 0 "${a[@]}")
    0
    >>> local a=(0 1 2 3 4 5)
    >>> echo $(array.slice 1 "${a[@]}")
    1
    >>> local a=(0 1 2 3 4 5)
    >>> array.slice 6 "${a[@]}"; echo $?
    1
    >>> local a=(0 1 2 3 4 5)
    >>> array.slice -7 "${a[@]}"; echo $?
    1
    '
    local start end array_length length
    if [[ $1 == *:* ]]; then
        IFS=":"; read -r start end <<<"$1"
        shift
        array_length="$#"
        # defaults
        [ -z "$end" ] && end=$array_length
        [ -z "$start" ] && start=0
        (( start < 0 )) && let "start=(( array_length + start ))"
        (( end < 0 )) && let "end=(( array_length + end ))"
    else
        start="$1"
        shift
        array_length="$#"
        (( start < 0 )) && let "start=(( array_length + start ))"
        let "end=(( start + 1 ))"
    fi
    let "length=(( end - start ))"
    (( start < 0 )) && return 1
    # check bounds
    (( length < 0 )) && return 1
    (( start < 0 )) && return 1
    (( start >= array_length )) && return 1
    # parameters start with $1, so add 1 to $start
    let "start=(( start + 1 ))"
    echo "${@: $start:$length}"
}
alias array.slice="array_slice"