我想知道如何在jQuery中使用Date()函数以yyyy/mm/dd格式获取当前日期。


当前回答

var d = new Date();
var month = d.getMonth() + 1;
var day = d.getDate();
var year = d.getYear();
var today = (day<10?'0':'')+ day + '/' +(month<10?'0':'')+ month + '/' + year;
alert(today);

其他回答

Moment.js让它变得非常简单:

moment().format("YYYY/MM/DD")

var today = new Date(); var tday = getfullyear () + '/' + ( today.getMonth() < 9 ?'0': " ) + (today.getMonth() + 1) + '/' + ( getdate () < 10 ?'0': " ) + today.getDate(); console.log (tday);

你可以在javascript中添加一个扩展方法。

Date.prototype.today = function () {
    return ((this.getDate() < 10) ? "0" : "") + this.getDate() + "/" + (((this.getMonth() + 1) < 10) ? "0" : "") + (this.getMonth() + 1) + "/" + this.getFullYear();
}

使用纯Javascript,你可以创建自己的YYYYMMDD格式原型;

Date.prototype.yyyymmdd = function() {
  var yyyy = this.getFullYear().toString();
  var mm = (this.getMonth()+1).toString(); // getMonth() is zero-based
  var dd  = this.getDate().toString();
  return yyyy + "/" + (mm[1]?mm:"0"+mm[0]) + "/" + (dd[1]?dd:"0"+dd[0]); // padding
};

var date = new Date();
console.log( date.yyyymmdd() ); // Assuming you have an open console
function returnCurrentDate() {
                var twoDigitMonth = ((fullDate.getMonth().toString().length) == 1) ? '0' + (fullDate.getMonth() + 1) : (fullDate.getMonth() + 1);
                var twoDigitDate = ((fullDate.getDate().toString().length) == 1) ? '0' + (fullDate.getDate()) : (fullDate.getDate());
                var currentDate = twoDigitDate + "/" + twoDigitMonth + "/" + fullDate.getFullYear();
                return currentDate;
            }