我看过这行代码

UIApplication.sharedApplication() .openURL(NSURL(string:"prefs:root=General")!)

是不工作，它没有为我在ios10/ Xcode 8，只是一个小的代码差异，请替换这个

UIApplication.sharedApplication().openURL(NSURL(string:"App-Prefs:root=General")!)

Swift3

UIApplication.shared.openURL(URL(string:"prefs:root=General")!)

替换为

UIApplication.shared.openURL(URL(string:"App-Prefs:root=General")!)

希望能有所帮助。 欢呼。

使用UIApplication.openSettingsURLString

Swift 5.1更新

 override func viewDidAppear(_ animated: Bool) {
    let alertController = UIAlertController (title: "Title", message: "Go to Settings?", preferredStyle: .alert)

    let settingsAction = UIAlertAction(title: "Settings", style: .default) { (_) -> Void in

        guard let settingsUrl = URL(string: UIApplication.openSettingsURLString) else {
            return
        }

        if UIApplication.shared.canOpenURL(settingsUrl) {
            UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
                print("Settings opened: \(success)") // Prints true
            })
        }
    }
    alertController.addAction(settingsAction)
    let cancelAction = UIAlertAction(title: "Cancel", style: .default, handler: nil)
    alertController.addAction(cancelAction)

    present(alertController, animated: true, completion: nil)
}

斯威夫特4.2

override func viewDidAppear(_ animated: Bool) {
    let alertController = UIAlertController (title: "Title", message: "Go to Settings?", preferredStyle: .alert)

    let settingsAction = UIAlertAction(title: "Settings", style: .default) { (_) -> Void in

        guard let settingsUrl = URL(string: UIApplicationOpenSettingsURLString) else {
            return
        }

        if UIApplication.shared.canOpenURL(settingsUrl) {
            UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
                print("Settings opened: \(success)") // Prints true
            })
        }
    }
    alertController.addAction(settingsAction)
    let cancelAction = UIAlertAction(title: "Cancel", style: .default, handler: nil)
    alertController.addAction(cancelAction)

    present(alertController, animated: true, completion: nil)
}

斯威夫特5

if let settingsUrl = URL(string: UIApplication.openSettingsURLString) {

   UIApplication.shared.open(settingsUrl)

 }

在iOS 8+中，您可以执行以下操作:

 func buttonClicked(sender:UIButton)
    {
        UIApplication.sharedApplication().openURL(NSURL(string: UIApplicationOpenSettingsURLString))
    }

斯威夫特4

    let settingsUrl = URL(string: UIApplicationOpenSettingsURLString)!
    UIApplication.shared.open(settingsUrl)

斯威夫特4

如果这是你想要的，这可能会占用你应用程序的特定设置。

UIApplication.shared.openURL(URL(string: UIApplicationOpenSettingsURLString)!)

App-Prefs:root=Privacy&path=LOCATION为我获得一般位置设置工作。注:仅在设备上有效。

剪力/ 12 +

open(url:options:completionHandler:)方法已经被更新为包含一个非空的选项字典，在这篇文章中只包含一个可能的UIApplication类型的选项。OpenExternalURLOptionsKey(在本例中)。

@objc func openAppSpecificSettings() {
    guard let url = URL(string: UIApplication.openSettingsURLString),
        UIApplication.shared.canOpenURL(url) else {
            return
    }
    let optionsKeyDictionary = [UIApplication.OpenExternalURLOptionsKey(rawValue: "universalLinksOnly"): NSNumber(value: true)]
    
    UIApplication.shared.open(url, options: optionsKeyDictionary, completionHandler: nil)
}

显式地构造一个URL，比如“App-Prefs”，会导致一些应用被商店拒绝。