在我重新发明这个特殊的轮子之前,有没有人有一个很好的用Python计算目录大小的例程?如果该例程能以Mb/Gb等格式格式化大小,那就太好了。
当前回答
下面的脚本打印指定目录的所有子目录的目录大小。它还试图(如果可能的话)从缓存递归函数的调用中获益。如果省略一个参数,脚本将在当前目录中工作。输出按目录大小从大到小排序。所以你可以根据自己的需要进行调整。
PS我已经使用配方578019以人性化的格式显示目录大小(http://code.activestate.com/recipes/578019/)
from __future__ import print_function
import os
import sys
import operator
def null_decorator(ob):
return ob
if sys.version_info >= (3,2,0):
import functools
my_cache_decorator = functools.lru_cache(maxsize=4096)
else:
my_cache_decorator = null_decorator
start_dir = os.path.normpath(os.path.abspath(sys.argv[1])) if len(sys.argv) > 1 else '.'
@my_cache_decorator
def get_dir_size(start_path = '.'):
total_size = 0
if 'scandir' in dir(os):
# using fast 'os.scandir' method (new in version 3.5)
for entry in os.scandir(start_path):
if entry.is_dir(follow_symlinks = False):
total_size += get_dir_size(entry.path)
elif entry.is_file(follow_symlinks = False):
total_size += entry.stat().st_size
else:
# using slow, but compatible 'os.listdir' method
for entry in os.listdir(start_path):
full_path = os.path.abspath(os.path.join(start_path, entry))
if os.path.isdir(full_path):
total_size += get_dir_size(full_path)
elif os.path.isfile(full_path):
total_size += os.path.getsize(full_path)
return total_size
def get_dir_size_walk(start_path = '.'):
total_size = 0
for dirpath, dirnames, filenames in os.walk(start_path):
for f in filenames:
fp = os.path.join(dirpath, f)
total_size += os.path.getsize(fp)
return total_size
def bytes2human(n, format='%(value).0f%(symbol)s', symbols='customary'):
"""
(c) http://code.activestate.com/recipes/578019/
Convert n bytes into a human readable string based on format.
symbols can be either "customary", "customary_ext", "iec" or "iec_ext",
see: http://goo.gl/kTQMs
>>> bytes2human(0)
'0.0 B'
>>> bytes2human(0.9)
'0.0 B'
>>> bytes2human(1)
'1.0 B'
>>> bytes2human(1.9)
'1.0 B'
>>> bytes2human(1024)
'1.0 K'
>>> bytes2human(1048576)
'1.0 M'
>>> bytes2human(1099511627776127398123789121)
'909.5 Y'
>>> bytes2human(9856, symbols="customary")
'9.6 K'
>>> bytes2human(9856, symbols="customary_ext")
'9.6 kilo'
>>> bytes2human(9856, symbols="iec")
'9.6 Ki'
>>> bytes2human(9856, symbols="iec_ext")
'9.6 kibi'
>>> bytes2human(10000, "%(value).1f %(symbol)s/sec")
'9.8 K/sec'
>>> # precision can be adjusted by playing with %f operator
>>> bytes2human(10000, format="%(value).5f %(symbol)s")
'9.76562 K'
"""
SYMBOLS = {
'customary' : ('B', 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y'),
'customary_ext' : ('byte', 'kilo', 'mega', 'giga', 'tera', 'peta', 'exa',
'zetta', 'iotta'),
'iec' : ('Bi', 'Ki', 'Mi', 'Gi', 'Ti', 'Pi', 'Ei', 'Zi', 'Yi'),
'iec_ext' : ('byte', 'kibi', 'mebi', 'gibi', 'tebi', 'pebi', 'exbi',
'zebi', 'yobi'),
}
n = int(n)
if n < 0:
raise ValueError("n < 0")
symbols = SYMBOLS[symbols]
prefix = {}
for i, s in enumerate(symbols[1:]):
prefix[s] = 1 << (i+1)*10
for symbol in reversed(symbols[1:]):
if n >= prefix[symbol]:
value = float(n) / prefix[symbol]
return format % locals()
return format % dict(symbol=symbols[0], value=n)
############################################################
###
### main ()
###
############################################################
if __name__ == '__main__':
dir_tree = {}
### version, that uses 'slow' [os.walk method]
#get_size = get_dir_size_walk
### this recursive version can benefit from caching the function calls (functools.lru_cache)
get_size = get_dir_size
for root, dirs, files in os.walk(start_dir):
for d in dirs:
dir_path = os.path.join(root, d)
if os.path.isdir(dir_path):
dir_tree[dir_path] = get_size(dir_path)
for d, size in sorted(dir_tree.items(), key=operator.itemgetter(1), reverse=True):
print('%s\t%s' %(bytes2human(size, format='%(value).2f%(symbol)s'), d))
print('-' * 80)
if sys.version_info >= (3,2,0):
print(get_dir_size.cache_info())
样例输出:
37.61M .\subdir_b
2.18M .\subdir_a
2.17M .\subdir_a\subdir_a_2
4.41K .\subdir_a\subdir_a_1
----------------------------------------------------------
CacheInfo(hits=2, misses=4, maxsize=4096, currsize=4)
编辑:根据user2233949的建议,将null_decorator移到上面
其他回答
它很方便:
import os
import stat
size = 0
path_ = ""
def calculate(path=os.environ["SYSTEMROOT"]):
global size, path_
size = 0
path_ = path
for x, y, z in os.walk(path):
for i in z:
size += os.path.getsize(x + os.sep + i)
def cevir(x):
global path_
print(path_, x, "Byte")
print(path_, x/1024, "Kilobyte")
print(path_, x/1048576, "Megabyte")
print(path_, x/1073741824, "Gigabyte")
calculate("C:\Users\Jundullah\Desktop")
cevir(size)
Output:
C:\Users\Jundullah\Desktop 87874712211 Byte
C:\Users\Jundullah\Desktop 85815148.64355469 Kilobyte
C:\Users\Jundullah\Desktop 83803.85609722137 Megabyte
C:\Users\Jundullah\Desktop 81.83970321994275 Gigabyte
这个脚本告诉您CWD中哪个文件最大,还告诉您文件在哪个文件夹中。 这个脚本适用于win8和python 3.3.3 shell
import os
folder=os.cwd()
number=0
string=""
for root, dirs, files in os.walk(folder):
for file in files:
pathname=os.path.join(root,file)
## print (pathname)
## print (os.path.getsize(pathname)/1024/1024)
if number < os.path.getsize(pathname):
number = os.path.getsize(pathname)
string=pathname
## print ()
print (string)
print ()
print (number)
print ("Number in bytes")
我在这里有点晚(和新),但我选择使用subprocess模块和Linux中的'du'命令行来检索文件夹大小的准确值,单位为MB。我必须使用if和elif用于根文件夹,否则子进程会由于返回的非零值而引发错误。
import subprocess
import os
#
# get folder size
#
def get_size(self, path):
if os.path.exists(path) and path != '/':
cmd = str(subprocess.check_output(['sudo', 'du', '-s', path])).\
replace('b\'', '').replace('\'', '').split('\\t')[0]
return float(cmd) / 1000000
elif os.path.exists(path) and path == '/':
cmd = str(subprocess.getoutput(['sudo du -s /'])). \
replace('b\'', '').replace('\'', '').split('\n')
val = cmd[len(cmd) - 1].replace('/', '').replace(' ', '')
return float(val) / 1000000
else: raise ValueError
这有点晚了,但只要安装了glob2和humanize,就行了。注意,在Python 3中,默认的iglob具有递归模式。如何修改Python 3的代码是留给读者的简单练习。
>>> import os
>>> from humanize import naturalsize
>>> from glob2 import iglob
>>> naturalsize(sum(os.path.getsize(x) for x in iglob('/var/**'))))
'546.2 MB'
使用pathlib,我想出了这个一行程序来获取文件夹的大小:
sum(file.stat().st_size for file in Path(folder).rglob('*'))
这是我为一个漂亮的格式化输出:
from pathlib import Path
def get_folder_size(folder):
return ByteSize(sum(file.stat().st_size for file in Path(folder).rglob('*')))
class ByteSize(int):
_KB = 1024
_suffixes = 'B', 'KB', 'MB', 'GB', 'PB'
def __new__(cls, *args, **kwargs):
return super().__new__(cls, *args, **kwargs)
def __init__(self, *args, **kwargs):
self.bytes = self.B = int(self)
self.kilobytes = self.KB = self / self._KB**1
self.megabytes = self.MB = self / self._KB**2
self.gigabytes = self.GB = self / self._KB**3
self.petabytes = self.PB = self / self._KB**4
*suffixes, last = self._suffixes
suffix = next((
suffix
for suffix in suffixes
if 1 < getattr(self, suffix) < self._KB
), last)
self.readable = suffix, getattr(self, suffix)
super().__init__()
def __str__(self):
return self.__format__('.2f')
def __repr__(self):
return '{}({})'.format(self.__class__.__name__, super().__repr__())
def __format__(self, format_spec):
suffix, val = self.readable
return '{val:{fmt}} {suf}'.format(val=val, fmt=format_spec, suf=suffix)
def __sub__(self, other):
return self.__class__(super().__sub__(other))
def __add__(self, other):
return self.__class__(super().__add__(other))
def __mul__(self, other):
return self.__class__(super().__mul__(other))
def __rsub__(self, other):
return self.__class__(super().__sub__(other))
def __radd__(self, other):
return self.__class__(super().__add__(other))
def __rmul__(self, other):
return self.__class__(super().__rmul__(other))
用法:
>>> size = get_folder_size("c:/users/tdavis/downloads")
>>> print(size)
5.81 GB
>>> size.GB
5.810891855508089
>>> size.gigabytes
5.810891855508089
>>> size.PB
0.005674699077644618
>>> size.MB
5950.353260040283
>>> size
ByteSize(6239397620)
我还遇到了这个问题,它有一些更紧凑、可能更高效的打印文件大小的策略。
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