我想在一个多余的config.ini中指定manage.py runserver侦听的默认端口。有没有比解析sys. exe更简单的解决方案?在manage.py和插入配置端口Argv ?

目标是运行./manage.py runserver,而不必每次都指定地址和端口,而是让它从config.ini中获取参数。


当前回答

在Pycharm中,可以简单地将端口添加到参数中

其他回答

对于Django 3。X,修改settings.py中的default_port。是这样的:

from decouple import config
import django.core.management.commands.runserver as runserver

runserver.Command.default_port = config('WebServer_Port', default = "8088")

然后,如果你想指定端口,只需在你的setting.ini中添加一个新行

[settings]
WebServer_Port=8091

如果不是,请删除该参数。

实际上,在Django服务器开发中修改(唯一)端口的最简单方法是:

python manage.py runserver 7000

它应该在http://127.0.0.1:7000/上运行开发服务器

下面所有的命令都可以在运行django时改变端口:

python manage.py runserver 127.0.0.1:7000

python manage.py runserver 7000

python manage.py runserver 0:7000

我们创建了一个新的“runserver”管理命令,它是标准命令的精简包装,但改变了默认端口。粗略地说,你创建management/commands/runserver.py并放入如下内容:

# Override the value of the constant coded into django...
import django.core.management.commands.runserver as runserver
runserver.DEFAULT_PORT="8001"

# ...print out a warning...
# (This gets output twice because runserver fires up two threads (one for autoreload).
#  We're living with it for now :-)
import os
dir_path = os.path.splitext(os.path.relpath(__file__))[0]
python_path = dir_path.replace(os.sep, ".")
print "Using %s with default port %s" % (python_path, runserver.DEFAULT_PORT)

# ...and then just import its standard Command class.
# Then manage.py runserver behaves normally in all other regards.
from django.core.management.commands.runserver import Command

在你的项目manage.py文件中添加

from django.core.management.commands.runserver import Command as runserver

然后在def main()中:

runserver.default_port = "8001"