Why don't you just put a hijacked onClick() event handler that will fire only when JS is enabled, and use this to append a parameter (js=true) to the clicked/selected URL (you could also detect a drop down list and change the value- of add a hidden form field). So now when the server sees this parameter (js=true) it knows that JS is enabled and then do your fancy logic server-side. The down side to this is that the first time a users comes to your site, bookmark, URL, search engine generated URL- you will need to detect that this is a new user so don't look for the NVP appended into the URL, and the server would have to wait for the next click to determine the user is JS enabled/disabled. Also, another downside is that the URL will end up on the browser URL and if this user then bookmarks this URL it will have the js=true NVP, even if the user does not have JS enabled, though on the next click the server would be wise to knowing whether the user still had JS enabled or not. Sigh.. this is fun...

这是我使用的“最干净”的解决方案:

<noscript>
    <style>
        body *{ /*hides all elements inside the body*/
            display: none;
        }
        h1{ /* even if this h1 is inside head tags it will be first hidden, so we have to display it again after all body elements are hidden*/
            display: block;
        }
    </style>
    <h1>JavaScript is not enabled, please check your browser settings.</h1>
</noscript>

也许听起来很奇怪，但你可以试一试:

<?php $jsEnabledVar = 0; ?>    

<script type="text/javascript">
var jsenabled = 1;
if(jsenabled == 1)
{
   <?php $jsEnabledVar = 1; ?>
}
</script>

<noscript>
var jsenabled = 0;
if(jsenabled == 0)
{
   <?php $jsEnabledVar = 0; ?>
}
</noscript>

现在在整个页面中使用'$jsEnabledVar'的值。你也可以用它来显示一个块，告诉用户JS被关闭了。

希望这能有所帮助

在什么地方发现它?JavaScript ?那是不可能的。如果只是为了记录日志，可以使用某种跟踪方案，其中每个页面都有JavaScript，将对一个特殊资源(可能是一个非常小的gif或类似的文件)发出请求。这样，您就可以获取唯一页面请求和跟踪文件请求之间的差异。

您会想看一下noscript标记。

<script type="text/javascript">
...some javascript script to insert data...
</script>
<noscript>
   <p>Access the <a href="http://someplace.com/data">data.</a></p>
</noscript>

我想添加我的解决方案，以获得可靠的统计数据，有多少真正的用户访问我的网站与javascript禁用的总用户。每节课只检查一次，有以下好处:

访问100个页面或仅访问1个页面的用户每人算1个。这允许只关注单个用户，而不是页面。 不打破页面流，结构或语义在任何方式 可以记录用户代理的日志。这允许排除机器人统计，如谷歌机器人和bing机器人通常有JS禁用!也可以记录IP，时间等… 每个会话只检查一次(最小的过载)

我的代码使用PHP, mysql和jquery与ajax，但可以适应其他语言:

在你的数据库中创建一个像这样的表:

CREATE TABLE IF NOT EXISTS `log_JS` (
  `logJS_id` int(11) NOT NULL AUTO_INCREMENT,
  `data_ins` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `session_id` varchar(50) NOT NULL,
  `JS_ON` tinyint(1) NOT NULL DEFAULT '0',
  `agent` varchar(255) DEFAULT NULL,
  PRIMARY KEY (`logJS_id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8;

在使用session_start()或等效(jquery必需)后将此添加到每个页面:

<?  if (!isset($_SESSION["JSTest"]))
    { 
        mysql_query("INSERT INTO log_JS (session_id, agent) VALUES ('" . mysql_real_escape_string(session_id()) . "', '" . mysql_real_escape_string($_SERVER['HTTP_USER_AGENT']). "')"); 
        $_SESSION["JSTest"] = 1; // One time per session
        ?>
        <script type="text/javascript">
            $(document).ready(function() { $.get('JSOK.php'); });
        </script>
        <?
    }
?>

像这样创建页面JSOK.php:

<?
include_once("[DB connection file].php");   
mysql_query("UPDATE log_JS SET JS_ON = 1 WHERE session_id = '" . mysql_real_escape_string(session_id()) . "'");