下面是一个很好的脚本，可以帮助你找到最有效的方法:

import timeit
from itertools import chain

string = "thisisthestringthatwewanttosplitintoalist"

def getCharList(str):
  return list(str)

def getCharListComp(str):
  return [char for char in str]

def getCharListMap(str):
  return list(map(lambda c: c, str))

def getCharListForLoop(str):
  list = []
  for c in str:
    list.append(c)

def getCharListUnpack(str):
  return [*str]

def getCharListExtend(str):
  list = []
  return list.extend(str)

def getCharListChain(str):
  return chain(str)
 
time_list = timeit.timeit(stmt='getCharList(string)', globals=globals(), number=1)
time_listcomp = timeit.timeit(stmt='getCharListComp(string)', globals=globals(), number=1)
time_listmap = timeit.timeit(stmt='getCharListMap(string)', globals=globals(), number=1)
time_listforloop = timeit.timeit(stmt='getCharListForLoop(string)', globals=globals(), number=1)
time_listunpack = timeit.timeit(stmt='getCharListUnpack(string)', globals=globals(), number=1)
time_listextend = timeit.timeit(stmt='getCharListExtend(string)', globals=globals(), number=1)
time_listchain = timeit.timeit(stmt='getCharListChain(string)', globals=globals(), number=1)

print(f"Execution time using list constructor is {time_list} seconds")
print(f"Execution time using list comprehension is {time_listcomp} seconds")
print(f"Execution time using map is {time_listmap} seconds")
print(f"Execution time using for loop is {time_listforloop} seconds")
print(f"Execution time using unpacking is {time_listunpack} seconds")
print(f"Execution time using extend is {time_listextend} seconds")
print(f"Execution time using chain is {time_listchain} seconds")

我探索了另外两种方法来完成这项任务。它可能对某人有帮助。

第一个很简单:

In [25]: a = []
In [26]: s = 'foobar'
In [27]: a += s
In [28]: a
Out[28]: ['f', 'o', 'o', 'b', 'a', 'r']

第二个使用map和函数。它可能适用于更复杂的任务:

In [36]: s = 'foobar12'
In [37]: a = map(lambda c: c, s)
In [38]: a
Out[38]: ['f', 'o', 'o', 'b', 'a', 'r', '1', '2']

例如

# isdigit, isspace or another facilities such as regexp may be used
In [40]: a = map(lambda c: c if c.isalpha() else '', s)
In [41]: a
Out[41]: ['f', 'o', 'o', 'b', 'a', 'r', '', '']

有关更多方法，请参阅python文档

下面是一个很好的脚本，可以帮助你找到最有效的方法:

import timeit
from itertools import chain

string = "thisisthestringthatwewanttosplitintoalist"

def getCharList(str):
  return list(str)

def getCharListComp(str):
  return [char for char in str]

def getCharListMap(str):
  return list(map(lambda c: c, str))

def getCharListForLoop(str):
  list = []
  for c in str:
    list.append(c)

def getCharListUnpack(str):
  return [*str]

def getCharListExtend(str):
  list = []
  return list.extend(str)

def getCharListChain(str):
  return chain(str)
 
time_list = timeit.timeit(stmt='getCharList(string)', globals=globals(), number=1)
time_listcomp = timeit.timeit(stmt='getCharListComp(string)', globals=globals(), number=1)
time_listmap = timeit.timeit(stmt='getCharListMap(string)', globals=globals(), number=1)
time_listforloop = timeit.timeit(stmt='getCharListForLoop(string)', globals=globals(), number=1)
time_listunpack = timeit.timeit(stmt='getCharListUnpack(string)', globals=globals(), number=1)
time_listextend = timeit.timeit(stmt='getCharListExtend(string)', globals=globals(), number=1)
time_listchain = timeit.timeit(stmt='getCharListChain(string)', globals=globals(), number=1)

print(f"Execution time using list constructor is {time_list} seconds")
print(f"Execution time using list comprehension is {time_listcomp} seconds")
print(f"Execution time using map is {time_listmap} seconds")
print(f"Execution time using for loop is {time_listforloop} seconds")
print(f"Execution time using unpacking is {time_listunpack} seconds")
print(f"Execution time using extend is {time_listextend} seconds")
print(f"Execution time using chain is {time_listchain} seconds")

你也可以用这种非常简单的方式来做，没有list():

>>> [c for c in "foobar"]
['f', 'o', 'o', 'b', 'a', 'r']

您也可以在列表操作中使用extend方法。

>>> list1 = []
>>> list1.extend('somestring')
>>> list1
['s', 'o', 'm', 'e', 's', 't', 'r', 'i', 'n', 'g']

Split()内置函数只会在特定条件的基础上分离值，但在单个词中，它不能满足条件。因此，可以借助list()来解决。它在内部调用数组，并根据数组存储值。

假设,

a = "bottle"
a.split() // will only return the word but not split the every single char.

a = "bottle"
list(a) // will separate ['b','o','t','t','l','e']