如何在Android应用程序中获取当前时间和日期?
当前回答
SimpleDateFormat databaseDateTimeFormate = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
SimpleDateFormat databaseDateFormate = new SimpleDateFormat("yyyy-MM-dd");
SimpleDateFormat sdf1 = new SimpleDateFormat("dd.MM.yy");
SimpleDateFormat sdf2 = new SimpleDateFormat("yyyy.MM.dd G 'at' hh:mm:ss z");
SimpleDateFormat sdf3 = new SimpleDateFormat("EEE, MMM d, ''yy");
SimpleDateFormat sdf4 = new SimpleDateFormat("h:mm a");
SimpleDateFormat sdf5 = new SimpleDateFormat("h:mm");
SimpleDateFormat sdf6 = new SimpleDateFormat("H:mm:ss:SSS");
SimpleDateFormat sdf7 = new SimpleDateFormat("K:mm a,z");
SimpleDateFormat sdf8 = new SimpleDateFormat("yyyy.MMMMM.dd GGG hh:mm aaa");
String currentDateandTime = databaseDateTimeFormate.format(new Date()); //2009-06-30 08:29:36
String currentDateandTime = databaseDateFormate.format(new Date()); //2009-06-30
String currentDateandTime = sdf1.format(new Date()); //30.06.09
String currentDateandTime = sdf2.format(new Date()); //2009.06.30 AD at 08:29:36 PDT
String currentDateandTime = sdf3.format(new Date()); //Tue, Jun 30, '09
String currentDateandTime = sdf4.format(new Date()); //8:29 PM
String currentDateandTime = sdf5.format(new Date()); //8:29
String currentDateandTime = sdf6.format(new Date()); //8:28:36:249
String currentDateandTime = sdf7.format(new Date()); //8:29 AM,PDT
String currentDateandTime = sdf8.format(new Date()); //2009.June.30 AD 08:29 AM
日期格式
G Era designator (before christ, after christ)
y Year (e.g. 12 or 2012). Use either yy or yyyy.
M Month in year. Number of M's determine length of format (e.g. MM, MMM or MMMMM)
d Day in month. Number of d's determine length of format (e.g. d or dd)
h Hour of day, 1-12 (AM / PM) (normally hh)
H Hour of day, 0-23 (normally HH)
m Minute in hour, 0-59 (normally mm)
s Second in minute, 0-59 (normally ss)
S Millisecond in second, 0-999 (normally SSS)
E Day in week (e.g Monday, Tuesday etc.)
D Day in year (1-366)
F Day of week in month (e.g. 1st Thursday of December)
w Week in year (1-53)
W Week in month (0-5)
a AM / PM marker
k Hour in day (1-24, unlike HH's 0-23)
K Hour in day, AM / PM (0-11)
z Time Zone
其他回答
Use:
Time time = new Time();
time.setToNow();
System.out.println("time: " + time.hour + ":" + time.minute);
例如,这将为您提供“12:32”。
记得导入android.text.format.Time;。
试试这段代码。它显示当前的日期和时间。
Date date = new Date(System.currentTimeMillis());
SimpleDateFormat dateFormat = new SimpleDateFormat("hh:mm aa",
Locale.ENGLISH);
String var = dateFormat.format(date));
要获取当前时间,您可以使用System.currentTimeMillis(),这是Java中的标准。然后您可以使用它来创建日期
Date currentDate = new Date(System.currentTimeMillis());
正如其他人提到的创造一个时间
Time currentTime = new Time();
currentTime.setToNow();
对于自定义的时间和日期格式:
SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZZZZZ",Locale.ENGLISH);
String cDateTime = dateFormat.format(new Date());
输出格式如下:
2015 - 06 - 18 - t10:15:56凌晨
实际上,使用time . getcurrenttimezone()在设备上设置当前时区更安全,否则您将获得UTC的当前时间。
Time today = new Time(Time.getCurrentTimezone());
today.setToNow();
然后,你可以得到你想要的所有日期字段,例如:
textViewDay.setText(today.monthDay + ""); // Day of the month (1-31)
textViewMonth.setText(today.month + ""); // Month (0-11)
textViewYear.setText(today.year + ""); // Year
textViewTime.setText(today.format("%k:%M:%S")); // Current time
详情请参阅android.text.format.Time类。
更新
正如许多人指出的那样,谷歌说这个类有一些问题,不应该再使用了:
This class has a number of issues and it is recommended that GregorianCalendar is used instead. Known issues: For historical reasons when performing time calculations all arithmetic currently takes place using 32-bit integers. This limits the reliable time range representable from 1902 until 2037.See the wikipedia article on the Year 2038 problem for details. Do not rely on this behavior; it may change in the future. Calling switchTimezone(String) on a date that cannot exist, such as a wall time that was skipped due to a DST transition, will result in a date in 1969 (i.e. -1, or 1 second before 1st Jan 1970 UTC). Much of the formatting / parsing assumes ASCII text and is therefore not suitable for use with non-ASCII scripts.
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