如何使用PHP找到两个日期之间的天数?
当前回答
$now = time(); // or your date as well
$your_date = strtotime("2010-01-31");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
其他回答
使用这个:)
$days = (strtotime($endDate) - strtotime($startDate)) / (60 * 60 * 24);
print $days;
现在起作用了
从PHP 5.3及以上版本开始,添加了新的日期/时间函数来获得不同:
$datetime1 = new DateTime("2010-06-20");
$datetime2 = new DateTime("2011-06-22");
$difference = $datetime1->diff($datetime2);
echo 'Difference: '.$difference->y.' years, '
.$difference->m.' months, '
.$difference->d.' days';
print_r($difference);
结果如下:
Difference: 1 years, 0 months, 2 days
DateInterval Object
(
[y] => 1
[m] => 0
[d] => 2
[h] => 0
[i] => 0
[s] => 0
[invert] => 0
[days] => 367
)
希望能有所帮助!
你可以通过简单的方法找到约会对象
<?php
$start = date_create('1988-08-10');
$end = date_create(); // Current time and date
$diff = date_diff( $start, $end );
echo 'The difference is ';
echo $diff->y . ' years, ';
echo $diff->m . ' months, ';
echo $diff->d . ' days, ';
echo $diff->h . ' hours, ';
echo $diff->i . ' minutes, ';
echo $diff->s . ' seconds';
// Output: The difference is 28 years, 5 months, 19 days, 20 hours, 34 minutes, 36 seconds
echo 'The difference in days : ' . $diff->days;
// Output: The difference in days : 10398
我阅读了所有以前的解决方案,没有一个使用PHP 5.3工具:DateTime::Diff和DateInterval::Days
DateInterval::Days精确地包含日期之间的天数。没有必要创造一些特别和奇异的东西。
/**
* We suppose that PHP is configured in UTC
* php.ini configuration:
* [Date]
* ; Defines the default timezone used by the date functions
* ; http://php.net/date.timezone
* date.timezone = UTC
* @link http://php.net/date.timezone
*/
/**
* getDaysBetween2Dates
*
* Return the difference of days between $date1 and $date2 ($date1 - $date2)
* if $absolute parameter is false, the return value is negative if $date2 is after than $date1
*
* @param DateTime $date1
* @param DateTime $date2
* @param Boolean $absolute
* = true
* @return integer
*/
function getDaysBetween2Dates(DateTime $date1, DateTime $date2, $absolute = true)
{
$interval = $date2->diff($date1);
// if we have to take in account the relative position (!$absolute) and the relative position is negative,
// we return negatif value otherwise, we return the absolute value
return (!$absolute and $interval->invert) ? - $interval->days : $interval->days;
}
echo '<h3>2020-03-01 - 2020-02-01: 29 days as it\'s a standard leap year</h3>';
echo getDaysBetween2Dates(new DateTime("2020-03-01"), new DateTime("2020-02-01"), false);
echo '<h3>1900-03-01 - 1900-02-01: 28 days as it\'s a "standard" century</h3>';
echo getDaysBetween2Dates(new DateTime("1900-03-01"), new DateTime("1900-02-01"), false);
echo '<h3>2000-03-01 - 2000-02-01: 29 days as it\'s a century multiple of 400: 2000=400x5</h3>';
echo getDaysBetween2Dates(new DateTime("2000-03-01"), new DateTime("2000-02-01"), false);
echo '<h3>2020-03-01 - 2020-04-01: -28 days as 2020-03-01 is before 2020-04-01</h3>';
echo getDaysBetween2Dates(new DateTime("2020-02-01"), new DateTime("2020-03-01"), false);
$now = time(); // or your date as well
$your_date = strtotime("2010-01-31");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
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