尝试OutputStream或者更具体地说FileOutputStream

基本的例子:

String fileName = "file.test";

BufferedOutputStream bs = null;

try {

    FileOutputStream fs = new FileOutputStream(new File(fileName));
    bs = new BufferedOutputStream(fs);
    bs.write(byte_array);
    bs.close();
    bs = null;

} catch (Exception e) {
    e.printStackTrace()
}

if (bs != null) try { bs.close(); } catch (Exception e) {}

没有任何库:

try (FileOutputStream stream = new FileOutputStream(path)) {
    stream.write(bytes);
}

谷歌番石榴:

Files.write(bytes, new File(path));

使用Apache Commons:

FileUtils.writeByteArrayToFile(new File(path), bytes);

所有这些策略都要求您在某个时刻捕获IOException。

////////////////////////// 1)文件字节 [] ///////////////////

Path path = Paths.get(p);
                    byte[] data = null;                         
                    try {
                        data = Files.readAllBytes(path);
                    } catch (IOException ex) {
                        Logger.getLogger(Agent1.class.getName()).log(Level.SEVERE, null, ex);
                    }

/////////////////////// 2] Byte[]文件 ///////////////////////////

 File f = new File(fileName);
 byte[] fileContent = msg.getByteSequenceContent();
Path path = Paths.get(f.getAbsolutePath());
                            try {
                                Files.write(path, fileContent);
                            } catch (IOException ex) {
                                Logger.getLogger(Agent2.class.getName()).log(Level.SEVERE, null, ex);
                            }

从Java 7开始，您可以使用try-with-resources语句来避免资源泄漏，并使您的代码更易于阅读。这里有更多。

要把你的byteArray写入一个文件，你会做:

try (FileOutputStream fos = new FileOutputStream("fullPathToFile")) {
    fos.write(byteArray);
} catch (IOException ioe) {
    ioe.printStackTrace();
}

File f = new File(fileName);    
byte[] fileContent = msg.getByteSequenceContent();    

Path path = Paths.get(f.getAbsolutePath());
try {
    Files.write(path, fileContent);
} catch (IOException ex) {
    Logger.getLogger(Agent2.class.getName()).log(Level.SEVERE, null, ex);
}