我的简单解决方案是按设备分组，支持新设备iPhone 8和iPhone X在Swift 3:

public extension UIDevice {
    var modelName: String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        let identifier = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8, value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }

        switch identifier {
        case "iPhone3,1", "iPhone3,2", "iPhone3,3", "iPhone4,1":
            return "iPhone 4"

        case "iPhone5,1", "iPhone5,2", "iPhone5,3", "iPhone5,4", "iPhone6,1", "iPhone6,2", "iPhone8,4":
            return "iPhone 5"

        case "iPhone7,2", "iPhone8,1", "iPhone9,1", "iPhone9,3", "iPhone10,1", "iPhone10,4":
            return "iPhone 6,7,8"

        case "iPhone7,1", "iPhone8,2", "iPhone9,2", "iPhone9,4", "iPhone10,2", "iPhone10,5":
            return "iPhone Plus"

        case "iPhone10,3", "iPhone10,6":
            return "iPhone X"

        case "i386", "x86_64":
            return "Simulator"
        default:
            return identifier
        }
    }
}

和使用:

switch UIDevice.current.modelName {
  case "iPhone 4":
  case "iPhone 5":
  case "iPhone 6,7,8":
  case "iPhone Plus":
  case "iPhone X":
  case "Simulator":
  default:
}

下面是获取硬件字符串的代码，但是您需要比较这些硬件字符串才能知道它是哪个设备。我已经创建了一个类，包含几乎所有的设备字符串(我们保持字符串最新的新设备)。使用方便，请检查

吉hub /恶魔大师

Objective-C: GitHub/DeviceUtil

public func hardwareString() -> String {
  var name: [Int32] = [CTL_HW, HW_MACHINE]
  var size: Int = 2
  sysctl(&name, 2, nil, &size, &name, 0)
  var hw_machine = [CChar](count: Int(size), repeatedValue: 0)
  sysctl(&name, 2, &hw_machine, &size, &name, 0)

  let hardware: String = String.fromCString(hw_machine)!
  return hardware
}

斯威夫特5

/// Obtain the machine hardware platform from the `uname()` unix command
///
/// Example of return values
///  - `"iPhone8,1"` = iPhone 6s
///  - `"iPad6,7"` = iPad Pro (12.9-inch)
static var unameMachine: String {
    var utsnameInstance = utsname()
    uname(&utsnameInstance)
    let optionalString: String? = withUnsafePointer(to: &utsnameInstance.machine) {
        $0.withMemoryRebound(to: CChar.self, capacity: 1) {
            ptr in String.init(validatingUTF8: ptr)
        }
    }
    return optionalString ?? "N/A"
}

extension UIDevice {

    public static let hardwareModel: String = {
        var path = [CTL_HW, HW_MACHINE]
        var n = 0
        sysctl(&path, 2, nil, &n, nil, 0)
        var a: [UInt8] = .init(repeating: 0, count: n)
        sysctl(&path, 2, &a, &n, nil, 0)
        return .init(cString: a)
    }()
}

UIDevice.hardwareModel // → iPhone9,3

struct utsname systemInfo;
uname(&systemInfo);

NSString* deviceModel = [NSString stringWithCString:systemInfo.machine
                          encoding:NSUTF8StringEncoding];

这里有一个辅助库。

斯威夫特5

吊舱“股息”，“~> 2.0”

Swift 4.0 - Swift 4.2

吊舱“股息”，“~> 1.3”

如果你只是想确定模型并做出相应的东西。

你可以这样用:

let isIphoneX = Device().isOneOf([.iPhoneX, .simulator(.iPhoneX)])

在函数中:

func isItIPhoneX() -> Bool {
    let device = Device()
    let check = device.isOneOf([.iPhoneX, .iPhoneXr , .iPhoneXs , .iPhoneXsMax ,
                                .simulator(.iPhoneX), .simulator(.iPhoneXr) , .simulator(.iPhoneXs) , .simulator(.iPhoneXsMax) ])
    return check
}