我如何使一个表达式匹配绝对任何东西(包括空白)?例子:

Regex:我买了_____羊。

火柴:我买了羊。我买了一只羊。我买了五只羊。

我尝试使用(.*),但似乎没有工作。


当前回答

(.*?)不适合我。我试图匹配注释周围的/* */,其中可能包含多行。

试试这个:

([a]|[^a])

这个正则表达式匹配a或除a之外的任何东西,当然,它意味着匹配所有东西。

顺便说一句,在我的情况下,/\*([a]|[^a])*/匹配C风格的注释。

感谢@mpen提供了一个更简洁的方式。

[\s\S]

其他回答

Regex: /I bought.*sheep./ Matches - the whole string till the end of line I bought sheep. I bought a sheep. I bought five sheep. Regex: /I bought(.*)sheep./ Matches - the whole string and also capture the sub string within () for further use I bought sheep. I bought a sheep. I bought five sheep. I boughtsheep. I bought a sheep. I bought fivesheep. Example using Javascript/Regex 'I bought sheep. I bought a sheep. I bought five sheep.'.match(/I bought(.*)sheep./)[0]; Output: "I bought sheep. I bought a sheep. I bought five sheep." 'I bought sheep. I bought a sheep. I bought five sheep.'.match(/I bought(.*)sheep./)[1]; Output: " sheep. I bought a sheep. I bought five "

/。如果没有换行符,*/效果很好。如果它必须匹配换行符,这里有一些解决方案:

Solution Description
/.*/s /s (dot all flag) makes . (wildcard character) match anything, including line breaks. Throw in an * (asterisk), and it will match everything. Read more.
/[\s\S]*/ \s (whitespace metacharacter) will match any whitespace character (space; tab; line break; ...), and \S (opposite of \s) will match anything that is not a whitespace character. * (asterisk) will match all occurrences of the character set (Encapsulated by []). Read more.

(.*?)不适合我。我试图匹配注释周围的/* */,其中可能包含多行。

试试这个:

([a]|[^a])

这个正则表达式匹配a或除a之外的任何东西,当然,它意味着匹配所有东西。

顺便说一句,在我的情况下,/\*([a]|[^a])*/匹配C风格的注释。

感谢@mpen提供了一个更简洁的方式。

[\s\S]

使用.*,并确保您使用的实现相当于单行,以便在行尾匹配。

这里有一个很好的解释-> http://www.regular-expressions.info/dot.html

老实说,很多答案都是旧的,所以我发现,如果你只是简单地测试任何字符串,不管字符内容“/。*/i"将充分获得所有内容。