Java中是否内置了一个函数，使字符串中每个单词的第一个字符大写，而不影响其他字符?
例子:
乔恩·斯基特->乔恩·斯基特 miles o'Brien -> miles o'Brien (B仍然是大写，这排除了Title Case) 老麦当劳->
*(老麦当劳也会被发现，但我不指望它有那么聪明。)
快速浏览一下Java字符串文档就会发现只有toUpperCase()和toLowerCase()，它们当然没有提供所需的行为。当然，谷歌的结果主要是这两个函数。它看起来像一个已经被发明出来的轮子，所以问一下也无妨，这样我以后就可以用它了。
当前回答
String s="hi dude i want apple";
s = s.replaceAll("\\s+"," ");
String[] split = s.split(" ");
s="";
for (int i = 0; i < split.length; i++) {
split[i]=Character.toUpperCase(split[i].charAt(0))+split[i].substring(1);
s+=split[i]+" ";
System.out.println(split[i]);
}
System.out.println(s);
其他回答
String s="hi dude i want apple";
s = s.replaceAll("\\s+"," ");
String[] split = s.split(" ");
s="";
for (int i = 0; i < split.length; i++) {
split[i]=Character.toUpperCase(split[i].charAt(0))+split[i].substring(1);
s+=split[i]+" ";
System.out.println(split[i]);
}
System.out.println(s);
我只想通过仅使用Java代码为该问题添加一个替代解决方案。 没有额外的库
public String Capitalize(String str) {
String tt = "";
String tempString = "";
String tempName = str.trim().toLowerCase();
String[] tempNameArr = tempName.split(" ");
System.out.println("The size is " + tempNameArr.length);
if (tempNameArr.length > 1) {
for (String t : tempNameArr) {
tt += Capitalize(t);
tt += " ";
}
tempString = tt;
} else {
tempString = tempName.replaceFirst(String.valueOf(tempName.charAt(0)), String.valueOf(tempName.charAt(0)).toUpperCase());
}
return tempString.trim();
}
1. Java 8流
public static String capitalizeAll(String str) {
if (str == null || str.isEmpty()) {
return str;
}
return Arrays.stream(str.split("\\s+"))
.map(t -> t.substring(0, 1).toUpperCase() + t.substring(1))
.collect(Collectors.joining(" "));
}
例子:
System.out.println(capitalizeAll("jon skeet")); // Jon Skeet
System.out.println(capitalizeAll("miles o'Brien")); // Miles O'Brien
System.out.println(capitalizeAll("old mcdonald")); // Old Mcdonald
System.out.println(capitalizeAll(null)); // null
对于foo bAR到foo bAR，替换map()方法如下:
.map(t -> t.substring(0, 1).toUpperCase() + t.substring(1).toLowerCase())
2. 字符串()(Java 9+)
ublic static String capitalizeAll(String str) {
if (str == null || str.isEmpty()) {
return str;
}
return Pattern.compile("\\b(.)(.*?)\\b")
.matcher(str)
.replaceAll(match -> match.group(1).toUpperCase() + match.group(2));
}
例子:
System.out.println(capitalizeAll("12 ways to learn java")); // 12 Ways To Learn Java
System.out.println(capitalizeAll("i am atta")); // I Am Atta
System.out.println(capitalizeAll(null)); // null
3.Apache Commons文本
System.out.println(WordUtils.capitalize("love is everywhere")); // Love Is Everywhere
System.out.println(WordUtils.capitalize("sky, sky, blue sky!")); // Sky, Sky, Blue Sky!
System.out.println(WordUtils.capitalize(null)); // null
titlecase:
System.out.println(WordUtils.capitalizeFully("fOO bAR")); // Foo Bar
System.out.println(WordUtils.capitalizeFully("sKy is BLUE!")); // Sky Is Blue!
有关详细信息，请查看本教程。
import java.io.*;
public class Upch2
{
BufferedReader br= new BufferedReader( new InputStreamReader(System.in));
public void main()throws IOException
{
System.out.println("Pl. Enter A Line");
String s=br.readLine();
String s1=" ";
s=" "+s;
int len=s.length();
s= s.toLowerCase();
for(int j=1;j<len;j++)
{
char ch=s.charAt(j);
if(s.charAt(j-1)!=' ')
{
ch=Character.toLowerCase((s.charAt(j)));
}
else
{
ch=Character.toUpperCase((s.charAt(j)));
}
s1=s1+ch;
}
System.out.println(" "+s1);
}
}
这里是RxJava解决方案的问题
String title = "this is a title";
StringBuilder stringBuilder = new StringBuilder();
Observable.fromArray(title.trim().split("\\s"))
.map(word -> word.substring(0, 1).toUpperCase() + word.substring(1).toLowerCase())
.toList()
.map(wordList -> {
for (String word : wordList) {
stringBuilder.append(word).append(" ");
}
return stringBuilder.toString();
})
.subscribe(result -> System.out.println(result));
不过我还不喜欢for循环。
