Java中是否内置了一个函数，使字符串中每个单词的第一个字符大写，而不影响其他字符?
例子:
乔恩·斯基特->乔恩·斯基特 miles o'Brien -> miles o'Brien (B仍然是大写，这排除了Title Case) 老麦当劳->
*(老麦当劳也会被发现，但我不指望它有那么聪明。)
快速浏览一下Java字符串文档就会发现只有toUpperCase()和toLowerCase()，它们当然没有提供所需的行为。当然，谷歌的结果主要是这两个函数。它看起来像一个已经被发明出来的轮子，所以问一下也无妨，这样我以后就可以用它了。
当前回答
String s="hi dude i want apple";
s = s.replaceAll("\\s+"," ");
String[] split = s.split(" ");
s="";
for (int i = 0; i < split.length; i++) {
split[i]=Character.toUpperCase(split[i].charAt(0))+split[i].substring(1);
s+=split[i]+" ";
System.out.println(split[i]);
}
System.out.println(s);
其他回答
Simple answer by program:
public class StringCamelCase {
public static void main(String[] args) {
String[] articles = {"the ", "a ", "one ", "some ", "any "};
String[] result = new String[articles.length];
int i = 0;
for (String string : articles) {
result[i++] = toUpercaseForstChar(string);
}
for (String string : result) {
System.out.println(string);
}
}
public static String toUpercaseForstChar(String string){
return new String(new char[]{string.charAt(0)}).toUpperCase() + string.substring(1,string.length());
}
}
public static void main(String[] args) throws IOException {
String words = "this is a test";
System.out.println(Arrays.asList(words.split(" ")).stream().reduce("",(a, b)->(a + " " + b.substring(0, 1).toUpperCase() + b.substring(1))));
}
}
这是另一种表达方式:
private String capitalize(String line)
{
StringTokenizer token =new StringTokenizer(line);
String CapLine="";
while(token.hasMoreTokens())
{
String tok = token.nextToken().toString();
CapLine += Character.toUpperCase(tok.charAt(0))+ tok.substring(1)+" ";
}
return CapLine.substring(0,CapLine.length()-1);
}
worddutil .capitalize(str) (from apache common -text)
(注意:如果你需要“fOO BAr”变成“fOO BAr”，那么用大写的(..)代替)
以下方法将所有字母转换为大写/小写，取决于它们靠近空格或其他特殊字符的位置。
public static String capitalizeString(String string) {
char[] chars = string.toLowerCase().toCharArray();
boolean found = false;
for (int i = 0; i < chars.length; i++) {
if (!found && Character.isLetter(chars[i])) {
chars[i] = Character.toUpperCase(chars[i]);
found = true;
} else if (Character.isWhitespace(chars[i]) || chars[i]=='.' || chars[i]=='\'') { // You can add other chars here
found = false;
}
}
return String.valueOf(chars);
}
