React Router 4中最简单的方法是使用

this.props.history.push('/new/url');

但是要使用此方法，您现有的组件应该能够访问历史对象。我们可以通过

If your component is linked to Route directly, then your component already has access to history object. eg: <Route path="/profile" component={ViewProfile}/> Here ViewProfile has access to history. If not connected to Route directly. eg: <Route path="/users" render={() => <ViewUsers/>} Then we have to use withRouter, a heigher order fuction to warp the existing component. Inside ViewUsers component import { withRouter } from 'react-router-dom'; export default withRouter(ViewUsers); That's it now, your ViewUsers component has access to history object.

更新

2-在这个场景中，将所有的路由道具传递给你的组件，然后我们可以从组件中访问this.props.history，即使没有一个HOC

eg:

<Route path="/users" render={props => <ViewUsers {...props} />}

使用回调。这对我很管用!

export function addProduct(props, callback) {
  return dispatch =>
    axios.post(`${ROOT_URL}/cart`, props, config)
    .then(response => {
    dispatch({ type: types.AUTH_USER });
    localStorage.setItem('token', response.data.token);
    callback();
  });
}

在组件中，你只需要添加回调

this.props.addProduct(props, () => this.props.history.push('/cart'))

React Router v4与v3(以及更早的版本)有本质上的不同，你不能像以前那样执行browserHistory.push()。

如果你想了解更多信息，这个讨论似乎是相关的:

创建一个新的browserHistory将不起作用，因为<BrowserRouter>创建了自己的历史实例，并侦听其上的更改。因此，不同的实例将更改url，但不更新<BrowserRouter>。 react-router不会在v4中公开browserHistory，只会在v2中公开。

相反，你有几个选择来做到这一点:

Use the withRouter high-order component Instead you should use the withRouter high order component, and wrap that to the component that will push to history. For example: import React from "react"; import { withRouter } from "react-router-dom"; class MyComponent extends React.Component { ... myFunction() { this.props.history.push("/some/Path"); } ... } export default withRouter(MyComponent); Check out the official documentation for more info: You can get access to the history object’s properties and the closest <Route>'s match via the withRouter higher-order component. withRouter will re-render its component every time the route changes with the same props as <Route> render props: { match, location, history }.

Use the context API Using the context might be one of the easiest solutions, but being an experimental API it is unstable and unsupported. Use it only when everything else fails. Here's an example: import React from "react"; import PropTypes from "prop-types"; class MyComponent extends React.Component { static contextTypes = { router: PropTypes.object } constructor(props, context) { super(props, context); } ... myFunction() { this.context.router.history.push("/some/Path"); } ... } Have a look at the official documentation on context: If you want your application to be stable, don't use context. It is an experimental API and it is likely to break in future releases of React. If you insist on using context despite these warnings, try to isolate your use of context to a small area and avoid using the context API directly when possible so that it's easier to upgrade when the API changes.

/*Step 1*/
myFunction(){  this.props.history.push("/home"); }
/**/
 <button onClick={()=>this.myFunction()} className={'btn btn-primary'}>Go 
 Home</button>

根据React Router v4文档- Redux深度集成会话

深度整合需要:

“能够通过调度操作进行导航”

然而，他们推荐这种方法作为“深度集成”的替代方案:

“你可以将提供给路由组件的历史对象传递给你的操作，而不是分派操作来导航。”

所以你可以用withRouter高阶组件来包装你的组件:

export default withthrouter (connect(null， {actionCreatorName})(ReactComponent));

它将历史API传递给道具。你可以调用动作创建者传递历史作为参数。例如，在你的ReactComponent中:

onClick={() => {
  this.props.actionCreatorName(
    this.props.history,
    otherParams
  );
}}

然后，在actions/index.js中:

export function actionCreatorName(history, param) {
  return dispatch => {
    dispatch({
      type: SOME_ACTION,
      payload: param.data
    });
    history.push("/path");
  };
}

你可以像我这样使用它来登录和曼尼不同的东西

class Login extends Component {
  constructor(props){
    super(props);
    this.login=this.login.bind(this)
  }


  login(){
this.props.history.push('/dashboard');
  }


render() {

    return (

   <div>
    <button onClick={this.login}>login</login>
    </div>

)