同样的话题也困扰着我。 我使用react-router-dom 5, Redux 4和BrowserRouter。 我更喜欢基于功能的组件和钩子。

像这样定义组件

import { useHistory } from "react-router-dom";
import { useDispatch } from "react-redux";

const Component = () => {
  ...
  const history = useHistory();
  dispatch(myActionCreator(otherValues, history));
};

你的动作创造者紧随其后

const myActionCreator = (otherValues, history) => async (dispatch) => {
  ...
  history.push("/path");
}

当然，如果不需要async，可以使用更简单的动作创建器

React Router 4中最简单的方法是使用

this.props.history.push('/new/url');

但是要使用此方法，您现有的组件应该能够访问历史对象。我们可以通过

If your component is linked to Route directly, then your component already has access to history object. eg: <Route path="/profile" component={ViewProfile}/> Here ViewProfile has access to history. If not connected to Route directly. eg: <Route path="/users" render={() => <ViewUsers/>} Then we have to use withRouter, a heigher order fuction to warp the existing component. Inside ViewUsers component import { withRouter } from 'react-router-dom'; export default withRouter(ViewUsers); That's it now, your ViewUsers component has access to history object.

更新

2-在这个场景中，将所有的路由道具传递给你的组件，然后我们可以从组件中访问this.props.history，即使没有一个HOC

eg:

<Route path="/users" render={props => <ViewUsers {...props} />}

我可以通过使用bind()来实现这一点。我想点击索引中的一个按钮。Jsx，向服务器发布一些数据，评估响应，并重定向到success.jsx。以下是我的计算方法……

index.jsx:

import React, { Component } from "react"
import { postData } from "../../scripts/request"

class Main extends Component {
    constructor(props) {
        super(props)
        this.handleClick = this.handleClick.bind(this)
        this.postData = postData.bind(this)
    }

    handleClick() {
        const data = {
            "first_name": "Test",
            "last_name": "Guy",
            "email": "test@test.com"
        }

        this.postData("person", data)
    }

    render() {
        return (
            <div className="Main">
                <button onClick={this.handleClick}>Test Post</button>
            </div>
        )
    }
}

export default Main

request.js:

import { post } from "./fetch"

export const postData = function(url, data) {
    // post is a fetch() in another script...
    post(url, data)
        .then((result) => {
            if (result.status === "ok") {
                this.props.history.push("/success")
            }
        })
}

success.jsx:

import React from "react"

const Success = () => {
    return (
        <div className="Success">
            Hey cool, got it.
        </div>
    )
}

export default Success

通过在index中绑定这个到postData。jsx，我能够访问this.props.history在request.js…那么我就可以在不同的组件中重用这个函数，只是要确保我记得包含这个。构造函数()中的postData = postData.bind(this)。

由于react router 5中已经包含了一个历史记录，因此我们可以通过参考访问相同的历史记录

import React from 'react';
import { BrowserRouter, Switch, Route } from 'react-router-dom';

function App() {
   const routerRef = React.useRef();
   const onProductNav = () => {
       const history = routerRef.current.history;
       history.push("product");
   }
return (
    <BrowserRouter ref={routerRef}>
        <Switch>
            <Route path="/product">
                <ProductComponent />
            </Route>
            <Route path="/">
                <HomeComponent />
            </Route>
        </Switch>
    </BrowserRouter>
)
}

React Router v4与v3(以及更早的版本)有本质上的不同，你不能像以前那样执行browserHistory.push()。

如果你想了解更多信息，这个讨论似乎是相关的:

创建一个新的browserHistory将不起作用，因为<BrowserRouter>创建了自己的历史实例，并侦听其上的更改。因此，不同的实例将更改url，但不更新<BrowserRouter>。 react-router不会在v4中公开browserHistory，只会在v2中公开。

相反，你有几个选择来做到这一点:

Use the withRouter high-order component Instead you should use the withRouter high order component, and wrap that to the component that will push to history. For example: import React from "react"; import { withRouter } from "react-router-dom"; class MyComponent extends React.Component { ... myFunction() { this.props.history.push("/some/Path"); } ... } export default withRouter(MyComponent); Check out the official documentation for more info: You can get access to the history object’s properties and the closest <Route>'s match via the withRouter higher-order component. withRouter will re-render its component every time the route changes with the same props as <Route> render props: { match, location, history }.

Use the context API Using the context might be one of the easiest solutions, but being an experimental API it is unstable and unsupported. Use it only when everything else fails. Here's an example: import React from "react"; import PropTypes from "prop-types"; class MyComponent extends React.Component { static contextTypes = { router: PropTypes.object } constructor(props, context) { super(props, context); } ... myFunction() { this.context.router.history.push("/some/Path"); } ... } Have a look at the official documentation on context: If you want your application to be stable, don't use context. It is an experimental API and it is likely to break in future releases of React. If you insist on using context despite these warnings, try to isolate your use of context to a small area and avoid using the context API directly when possible so that it's easier to upgrade when the API changes.

同样的话题也困扰着我。 我使用react-router-dom 5, Redux 4和BrowserRouter。 我更喜欢基于功能的组件和钩子。

像这样定义组件

import { useHistory } from "react-router-dom";
import { useDispatch } from "react-redux";

const Component = () => {
  ...
  const history = useHistory();
  dispatch(myActionCreator(otherValues, history));
};

你的动作创造者紧随其后

const myActionCreator = (otherValues, history) => async (dispatch) => {
  ...
  history.push("/path");
}

当然，如果不需要async，可以使用更简单的动作创建器