为了使它完整，也可以这样做:

echo "a,b" | sed "s/,/\\$(echo -e '\n\r')/"

FWIW，下面的行工作在窗口和替换分号在我的路径变量换行。我正在使用安装在我的git bin目录下的工具。

echo %path% | sed -e $'s/;/\\n/g' | less

如果sed的使用倾向于完全使用替换表达式(就像我的一样)，您也可以使用perl -pe来代替

$ echo 'foo,bar,baz' | perl -pe 's/,/,\n/g'
foo,
bar,
baz

请改用tr:

tr , '\n' < file

我发现了另一个同样有效的命令。

find your_filename.txt -type f -exec sed -i 's/,/\n/g' {} \;

只是为了澄清:OSX上sed的手册页(10.8;达尔文内核版本12.4.0)说:

[…]

Sed正则表达式

 The regular expressions used in sed, by default, are basic regular expressions (BREs, see re_format(7) for more information), but extended
 (modern) regular expressions can be used instead if the -E flag is given.  In addition, sed has the following two additions to regular
 expressions:

 1.   In a context address, any character other than a backslash (``\'') or newline character may be used to delimit the regular expression.
      Also, putting a backslash character before the delimiting character causes the character to be treated literally.  For example, in the
      context address \xabc\xdefx, the RE delimiter is an ``x'' and the second ``x'' stands for itself, so that the regular expression is
      ``abcxdef''.

 2.   The escape sequence \n matches a newline character embedded in the pattern space.  You cannot, however, use a literal newline charac-
      ter in an address or in the substitute command.

[…]

所以我想一个人必须使用tr -如上所述-或者nitty

sed "s/,/^M
/g"

注意:你必须输入<ctrl>-v，<return>才能在vi编辑器中得到'^M'