你可以通过以下方法检查箭头键是否被按下:

$(document).keydown(function(e){
    if (e.keyCode > 36 && e.keyCode < 41) { 
       alert( "arrowkey pressed" );
       return false;
    }
});

一个健壮的Javascript库，用于捕获键盘输入和输入的组合键。它没有依赖关系。

http://jaywcjlove.github.io/hotkeys/

hotkeys('right,left,up,down', function(e, handler){
    switch(handler.key){
        case "right":console.log('right');break
        case "left":console.log('left');break
        case "up":console.log('up');break
        case "down":console.log('down');break
    }
});

我只是把其他答案中最好的部分结合起来:

$(document).keydown(function(e){
    switch(e.which) {
        case $.ui.keyCode.LEFT:
        // your code here
        break;

        case $.ui.keyCode.UP:
        // your code here
        break;

        case $.ui.keyCode.RIGHT:
        // your code here
        break;

        case $.ui.keyCode.DOWN:
        // your code here
        break;

        default: return; // allow other keys to be handled
    }

    // prevent default action (eg. page moving up/down)
    // but consider accessibility (eg. user may want to use keys to choose a radio button)
    e.preventDefault();
});

咖啡和Jquery

  $(document).on 'keydown', (e) ->
    switch e.which
      when 37 then console.log('left key')
      when 38 then console.log('up key')
      when 39 then console.log('right key')
      when 40 then console.log('down key')
    e.preventDefault()

使用纯Javascript的简洁解决方案(感谢Sygmoral提出的改进建议):

document.onkeydown = function(e) {
    switch (e.keyCode) {
        case 37:
            alert('left');
            break;
        case 39:
            alert('right');
            break;
    }
};

参见https://stackoverflow.com/a/17929007/1397061。

你可以使用KeyboardJS。我为这样的任务编写了库。

KeyboardJS.on('up', function() { console.log('up'); });
KeyboardJS.on('down', function() { console.log('down'); });
KeyboardJS.on('left', function() { console.log('right'); });
KeyboardJS.on('right', function() { console.log('left'); });

在这里签出库=> http://robertwhurst.github.com/KeyboardJS/