Typescript输入onchange event.target.value

在我的react和typescript应用程序中，我使用:

onChange={(e) => data.motto = (e.target as any).value}

我如何正确地定义类的类型，这样我就不必用任何类型系统来破解我的方法?

export interface InputProps extends React.HTMLProps<Input> {
...

}

export class Input extends React.Component<InputProps, {}> {
}

如果我放target: {value: string};我得到:

ERROR in [default] /react-onsenui.d.ts:87:18
Interface 'InputProps' incorrectly extends interface 'HTMLProps<Input>'.
  Types of property 'target' are incompatible.
    Type '{ value: string; }' is not assignable to type 'string'.

当前回答

在TypeScript中使用的正确方法是

  handleChange(e: React.ChangeEvent<HTMLInputElement>) {
    // No longer need to cast to any - hooray for react!
    this.setState({temperature: e.target.value});
  }

  render() {
        ...
        <input value={temperature} onChange={this.handleChange} />
        ...
    );
  }

遵循完整的类，更好地理解:

import * as React from "react";

const scaleNames = {
  c: 'Celsius',
  f: 'Fahrenheit'
};


interface TemperatureState {
   temperature: string;
}

interface TemperatureProps {
   scale: string;

}

class TemperatureInput extends React.Component<TemperatureProps, TemperatureState> {
  constructor(props: TemperatureProps) {
    super(props);
    this.handleChange = this.handleChange.bind(this);
    this.state = {temperature: ''};
  }

  //  handleChange(e: { target: { value: string; }; }) {
  //    this.setState({temperature: e.target.value});  
  //  }


  handleChange(e: React.ChangeEvent<HTMLInputElement>) {
    // No longer need to cast to any - hooray for react!
    this.setState({temperature: e.target.value});
  }

  render() {
    const temperature = this.state.temperature;
    const scale = this.props.scale;
    return (
      <fieldset>
        <legend>Enter temperature in {scaleNames[scale]}:</legend>
        <input value={temperature} onChange={this.handleChange} />
      </fieldset>
    );
  }
}

export default TemperatureInput;

2018-04-13 15:08:06

其他回答

as HTMLInputElement为我工作

2017-02-08 04:16:12

我使用的方法是这样的:

import { ChangeEvent, useState } from 'react';


export const InputChange = () => {
  const [state, setState] = useState({ value: '' });

  const handleChange = (event: ChangeEvent<{ value: string }>) => {
    setState({ value: event?.currentTarget?.value });
  }
  return (
    <div>
      <input onChange={handleChange} />
      <p>{state?.value}</p>
    </div>
  );
}

2020-12-31 16:50:41

import { NativeSyntheticEvent, TextInputChangeEventData,} from 'react-native';



  // Todo in java script
 const onChangeTextPassword = (text : any) => {
    setPassword(text);
  }

// Todo在类型脚本中使用这个

  const onChangeTextEmail = ({ nativeEvent: { text },}: NativeSyntheticEvent<TextInputChangeEventData>) => {
    console.log("________ onChangeTextEmail _________ "+ text);
    setEmailId(text);
  };


 <TextInput
          style={{ width: '100%', borderBottomWidth: 1, borderBottomColor: 'grey', height: 40, }}
          autoCapitalize="none"
          returnKeyType="next"
          maxLength={50}
          secureTextEntry={false}
          onChange={onChangeTextEmail}
          value={emailId}
          defaultValue={emailId}
          
        />

2021-09-20 13:33:37

这也适用于我，它是框架不可知论者。

const handler = (evt: Event) => {
  console.log((evt.target as HTMLInputElement).value))
}

2022-04-26 03:32:42

您可以执行以下操作:

import { ChangeEvent } from 'react';

const onChange = (e: ChangeEvent<HTMLInputElement>)=> {
   const newValue = e.target.value;
}

2018-02-09 06:44:43

Typescript输入onchange event.target.value

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