使用Apache Commons StringUtils。leftPad(或者查看代码来创建自己的函数)。

有人尝试过这个纯Java解决方案吗(没有SpringUtils):

//decimal to hex string 1=> 01, 10=>0A,..
String.format("%1$2s", Integer.toString(1,16) ).replace(" ","0");
//reply to original question, string with leading zeros. 
//first generates a 10 char long string with leading spaces, and then spaces are
//replaced by a zero string. 
String.format("%1$10s", "mystring" ).replace(" ","0");

不幸的是，这个解决方案只有在字符串中没有空格时才有效。

使用Guava的Strings实用程序类:

Strings.padStart("Apple", 8, '0');

可以更快，然后克里斯勒彻回答时，大部分的字符串恰好有8个字符

int length = in.length();
return length == 8 ? in : ("00000000" + in).substring(length);

在我的情况下，我的机器快了1/8。

public class LeadingZerosExample {
    public static void main(String[] args) {
       int number = 1500;

       // String format below will add leading zeros (the %0 syntax) 
       // to the number above. 
       // The length of the formatted string will be 7 characters.

       String formatted = String.format("%07d", number);

       System.out.println("Number with leading zeros: " + formatted);
    }
}

public class PaddingLeft {
    public static void main(String[] args) {
        String input = "Apple";
        String result = "00000000" + input;
        int length = result.length();
        result = result.substring(length - 8, length);
        System.out.println(result);
    }
}