下面是字符串,例如:
"Apple"
我想加零来填充8个字符:
"000Apple"
我该怎么做呢?
下面是字符串,例如:
"Apple"
我想加零来填充8个字符:
"000Apple"
我该怎么做呢?
当前回答
String input = "Apple";
StringBuffer buf = new StringBuffer(input);
while (buf.length() < 8) {
buf.insert(0, '0');
}
String output = buf.toString();
其他回答
我相信这就是他真正想要的:
String.format("%0"+ (8 - "Apple".length() )+"d%s",0 ,"Apple");
输出:
000Apple
使用Apache Commons StringUtils。leftPad(或者查看代码来创建自己的函数)。
String input = "Apple";
StringBuffer buf = new StringBuffer(input);
while (buf.length() < 8) {
buf.insert(0, '0');
}
String output = buf.toString();
有人尝试过这个纯Java解决方案吗(没有SpringUtils):
//decimal to hex string 1=> 01, 10=>0A,..
String.format("%1$2s", Integer.toString(1,16) ).replace(" ","0");
//reply to original question, string with leading zeros.
//first generates a 10 char long string with leading spaces, and then spaces are
//replaced by a zero string.
String.format("%1$10s", "mystring" ).replace(" ","0");
不幸的是,这个解决方案只有在字符串中没有空格时才有效。
public class PaddingLeft {
public static void main(String[] args) {
String input = "Apple";
String result = "00000000" + input;
int length = result.length();
result = result.substring(length - 8, length);
System.out.println(result);
}
}