我知道这是一个非常普遍的问题,但我在Angular 2中上传文件失败了。 我试过了
1) http://valor-software.com/ng2-file-upload/
2) http://ng2-uploader.com/home
...但失败了。有人在Angular中上传过文件吗?你用了什么方法?怎么做呢?如果提供了任何示例代码或演示链接,将非常感谢。
我知道这是一个非常普遍的问题,但我在Angular 2中上传文件失败了。 我试过了
1) http://valor-software.com/ng2-file-upload/
2) http://ng2-uploader.com/home
...但失败了。有人在Angular中上传过文件吗?你用了什么方法?怎么做呢?如果提供了任何示例代码或演示链接,将非常感谢。
当前回答
感谢@Eswar。这段代码非常适合我。我想在解决方案中添加一些东西:
我得到错误:java.io.IOException: RESTEASY007550:无法获得多部分的边界
为了解决这个错误,你应该删除“Content-Type”“multipart/form-data”。它解决了我的问题。
其他回答
这个简单的解决方案对我很有效:file-upload.component.html
<div>
<input type="file" #fileInput placeholder="Upload file..." />
<button type="button" (click)="upload()">Upload</button>
</div>
然后在组件中直接使用XMLHttpRequest进行上传。
import { Component, OnInit, ViewChild } from '@angular/core';
@Component({
selector: 'app-file-upload',
templateUrl: './file-upload.component.html',
styleUrls: ['./file-upload.component.css']
})
export class FileUploadComponent implements OnInit {
@ViewChild('fileInput') fileInput;
constructor() { }
ngOnInit() {
}
private upload() {
const fileBrowser = this.fileInput.nativeElement;
if (fileBrowser.files && fileBrowser.files[0]) {
const formData = new FormData();
formData.append('files', fileBrowser.files[0]);
const xhr = new XMLHttpRequest();
xhr.open('POST', '/api/Data/UploadFiles', true);
xhr.onload = function () {
if (this['status'] === 200) {
const responseText = this['responseText'];
const files = JSON.parse(responseText);
//todo: emit event
} else {
//todo: error handling
}
};
xhr.send(formData);
}
}
}
如果使用dotnet core,参数名必须与from字段名匹配。本例中的文件:
[HttpPost("[action]")]
public async Task<IList<FileDto>> UploadFiles(List<IFormFile> files)
{
return await _binaryService.UploadFilesAsync(files);
}
这个答案抄袭了http://blog.teamtreehouse.com/uploading-files-ajax
编辑: 上传后,您必须清除文件上传,以便用户可以选择一个新文件。与其使用XMLHttpRequest,不如使用fetch:
private addFileInput() {
const fileInputParentNative = this.fileInputParent.nativeElement;
const oldFileInput = fileInputParentNative.querySelector('input');
const newFileInput = document.createElement('input');
newFileInput.type = 'file';
newFileInput.multiple = true;
newFileInput.name = 'fileInput';
const uploadfiles = this.uploadFiles.bind(this);
newFileInput.onchange = uploadfiles;
oldFileInput.parentNode.replaceChild(newFileInput, oldFileInput);
}
private uploadFiles() {
this.onUploadStarted.emit();
const fileInputParentNative = this.fileInputParent.nativeElement;
const fileInput = fileInputParentNative.querySelector('input');
if (fileInput.files && fileInput.files.length > 0) {
const formData = new FormData();
for (let i = 0; i < fileInput.files.length; i++) {
formData.append('files', fileInput.files[i]);
}
const onUploaded = this.onUploaded;
const onError = this.onError;
const addFileInput = this.addFileInput.bind(this);
fetch('/api/Data/UploadFiles', {
credentials: 'include',
method: 'POST',
body: formData,
}).then((response: any) => {
if (response.status !== 200) {
const error = `An error occured. Status: ${response.status}`;
throw new Error(error);
}
return response.json();
}).then(files => {
onUploaded.emit(files);
addFileInput();
}).catch((error) => {
onError.emit(error);
});
}
https://github.com/yonexbat/cran/blob/master/cranangularclient/src/app/file-upload/file-upload.component.ts
在Angular 2+中,让Content-Type为空是非常重要的。如果您将“内容类型”设置为“multipart/form-data”,则上传将无法工作!
upload.component.html
<input type="file" (change)="fileChange($event)" name="file" />
upload.component.ts
export class UploadComponent implements OnInit {
constructor(public http: Http) {}
fileChange(event): void {
const fileList: FileList = event.target.files;
if (fileList.length > 0) {
const file = fileList[0];
const formData = new FormData();
formData.append('file', file, file.name);
const headers = new Headers();
// It is very important to leave the Content-Type empty
// do not use headers.append('Content-Type', 'multipart/form-data');
headers.append('Authorization', 'Bearer ' + 'eyJhbGciOiJSUzI1NiIsInR5cCI6IkpXVCJ9....');
const options = new RequestOptions({headers: headers});
this.http.post('https://api.mysite.com/uploadfile', formData, options)
.map(res => res.json())
.catch(error => Observable.throw(error))
.subscribe(
data => console.log('success'),
error => console.log(error)
);
}
}
}
下面的代码以最简单的形式在Angular 6/7中工作
this.http.post("http://destinationurl.com/endpoint", fileFormData)
.subscribe(response => {
//handle response
}, err => {
//handle error
});
下面是完整的实现
上传带有表单字段的图像
SaveFileWithData(article: ArticleModel,picture:File): Observable<ArticleModel>
{
let headers = new Headers();
// headers.append('Content-Type', 'multipart/form-data');
// headers.append('Accept', 'application/json');
let requestoptions = new RequestOptions({
method: RequestMethod.Post,
headers:headers
});
let formData: FormData = new FormData();
if (picture != null || picture != undefined) {
formData.append('files', picture, picture.name);
}
formData.append("article",JSON.stringify(article));
return this.http.post("url",formData,requestoptions)
.map((response: Response) => response.json() as ArticleModel);
}
在我的情况下,我需要。net Web Api在c#
// POST: api/Articles
[ResponseType(typeof(Article))]
public async Task<IHttpActionResult> PostArticle()
{
Article article = null;
try
{
HttpPostedFile postedFile = null;
var httpRequest = HttpContext.Current.Request;
if (httpRequest.Files.Count == 1)
{
postedFile = httpRequest.Files[0];
var filePath = HttpContext.Current.Server.MapPath("~/" + postedFile.FileName);
postedFile.SaveAs(filePath);
}
var json = httpRequest.Form["article"];
article = JsonConvert.DeserializeObject <Article>(json);
if (!ModelState.IsValid)
{
return BadRequest(ModelState);
}
article.CreatedDate = DateTime.Now;
article.CreatedBy = "Abbas";
db.articles.Add(article);
await db.SaveChangesAsync();
}
catch (Exception ex)
{
int a = 0;
}
return CreatedAtRoute("DefaultApi", new { id = article.Id }, article);
}
这是一个有用的教程,如何使用ng2-file-upload和不使用ng2-file-upload上传文件。
对我来说很有帮助。
目前,教程包含几个错误:
1-客户端应具有与服务器相同的上传url 在app.component.ts中更改行
const URL = 'http://localhost:8000/api/upload';
to
const URL = 'http://localhost:3000';
2-服务器发送响应为'text/html',所以在app.component.ts更改
.post(URL, formData).map((res:Response) => res.json()).subscribe(
//map the success function and alert the response
(success) => {
alert(success._body);
},
(error) => alert(error))
来
.post(URL, formData)
.subscribe((success) => alert('success'), (error) => alert(error));