在Swift中声明和初始化字典

字符串字典

var stringDict: [String: String] = [String: String]()

OR

var stringDict: Dictionary<String, String> = Dictionary<String, String>()

Int字典

var stringDict: [String: Int] = [String: Int]()

OR

var stringDict: Dictionary<String, Int> = Dictionary<String, Int>()

AnyObject字典

var stringDict: [String: AnyObject] = [String: AnyObject]()

OR

var stringDict: Dictionary<String, AnyObject> = Dictionary<String, AnyObject>()

字符串数组字典

var stringDict: [String: [String]] = [String: [String]]()

OR

var stringDict: Dictionary<String, Array<String>> = Dictionary<String, Array<String>>()

字符串字典数组

var stringDict: [[String: String]] = [[String: String]]()

OR

var stringDict: Array<Dictionary<String, String>> = Array<Dictionary<String, String>>()

我通常用

var dictionary:[String:String] = [:]
dictionary.removeAll()

var dictList = String: swift中字典的字符串 var arrSectionTitle =字符串数组在swift

用这个会有用的。

var emptyDict = [String: String]()

我也在玩这个。看起来很奇怪，你可以声明一个空字典，然后像这样添加一个键/值对:

var emptyDictionary = Dictionary<String, Float>()
var flexDictionary = [:]
emptyDictionary["brian"] = 4.5
flexDictionary["key"] = "value" // ERROR : cannot assign to the result of this expression

但是你可以通过使用"Any"类型创建一个接受不同值类型的Dictionary，如下所示:

var emptyDictionary = Dictionary<String, Any>()
emptyDictionary["brian"] = 4.5
emptyDictionary["mike"] = "hello"

当你在Swift中声明任何东西时，你需要显式地告诉数据类型或类型可以推断。

斯威夫特3

下面的示例声明了一个字典，其中key为Int类型，value为String类型。

方法1:初始化器

let dic = Dictionary<Int, String>()

方法二:简写语法

let dic = [Int:String]()

方法3:字典直译

var dic = [1: "Sample"]
// dic has NOT to be a constant
dic.removeAll()