这是一个常见的问题,但我不知道如何解决它。下面的代码可以正常工作。

var mind = time % (60 * 60);
var minutes = Math.floor(mind / 60);
         
var secd = mind % 60;
var seconds = Math.ceil(secd);

然而,当我到达1小时或3600秒时,它返回0分和0秒。我如何避免这种情况,让它返回所有的分钟?


当前回答

  function formatSeconds(s: number) {
    let minutes = ~~(s / 60);
    let seconds = ~~(s % 60);
    return minutes + ':' + seconds;
  }

其他回答

Day.js

如果你使用day.js,试试这个。

const dayjs = require('dayjs')
const duration = require('dayjs/plugin/duration') 
dayjs.extend(duration)

const time = dayjs.duration(100, 'seconds')

time.seconds() // 40
time.minutes() // 1
time.format('mm:ss') // 01:40

对于那些希望能快速简单地将秒格式化为M:SS的人来说:

function fmtMSS(s){return(s-(s%=60))/60+(9<s?':':':0')+s}

做. . 该函数接受一个数字(首选)或一个字符串(2转换'惩罚',你可以通过在函数调用的参数s中前置+来减半,如:fmtMSS(+strSeconds)),表示正整数秒s作为参数。

例子:

fmtMSS(    0 );  //   0:00
fmtMSS(   '8');  //   0:08
fmtMSS(    9 );  //   0:09
fmtMSS(  '10');  //   0:10
fmtMSS(   59 );  //   0:59
fmtMSS( +'60');  //   1:00
fmtMSS(   69 );  //   1:09
fmtMSS( 3599 );  //  59:59
fmtMSS('3600');  //  60:00
fmtMSS('3661');  //  61:01
fmtMSS( 7425 );  // 123:45

分解:

function fmtMSS(s){   // accepts seconds as Number or String. Returns m:ss
  return( s -         // take value s and subtract (will try to convert String to Number)
          ( s %= 60 ) // the new value of s, now holding the remainder of s divided by 60 
                      // (will also try to convert String to Number)
        ) / 60 + (    // and divide the resulting Number by 60 
                      // (can never result in a fractional value = no need for rounding)
                      // to which we concatenate a String (converts the Number to String)
                      // who's reference is chosen by the conditional operator:
          9 < s       // if    seconds is larger than 9
          ? ':'       // then  we don't need to prepend a zero
          : ':0'      // else  we do need to prepend a zero
        ) + s ;       // and we add Number s to the string (converting it to String as well)
}

注意:负数范围可以通过在返回表达式前加上(0>s?(s=-s,'-'): ")+来增加(实际上,(0>s?(s=-s,'-'):0)+也可以)。

要添加前导零,我只需这样做:

const secondstom昆虫填充=时间=> { const minutes = "0" + Math。楼层(时间/ 60); Const seconds = "0" +(时间-分钟* 60); 返回minutes.substr(-2) + ":" + seconds.substr(-2); }; console.log (secondsToMinSecPadded (241));

很好,很短

秒到h:mm:ss

var hours = Math.floor(time / 3600);
time -= hours * 3600;

var minutes = Math.floor(time / 60);
time -= minutes * 60;

var seconds = parseInt(time % 60, 10);

console.log(hours + ':' + (minutes < 10 ? '0' + minutes : minutes) + ':' + (seconds < 10 ? '0' + seconds : seconds));
function secondsToMinutes(time){
    return Math.floor(time / 60)+':'+Math.floor(time % 60);
}