这是一个常见的问题，但我不知道如何解决它。下面的代码可以正常工作。
var mind = time % (60 * 60);
var minutes = Math.floor(mind / 60);
var secd = mind % 60;
var seconds = Math.ceil(secd);
然而，当我到达1小时或3600秒时，它返回0分和0秒。我如何避免这种情况，让它返回所有的分钟?
当前回答
试试这个: 将秒转换为小时，分钟和秒。
function convertTime(sec) {
var hours = Math.floor(sec/3600);
(hours >= 1) ? sec = sec - (hours*3600) : hours = '00';
var min = Math.floor(sec/60);
(min >= 1) ? sec = sec - (min*60) : min = '00';
(sec < 1) ? sec='00' : void 0;
(min.toString().length == 1) ? min = '0'+min : void 0;
(sec.toString().length == 1) ? sec = '0'+sec : void 0;
return hours+':'+min+':'+sec;
}
其他回答
对于那些希望能快速简单地将秒格式化为M:SS的人来说:
function fmtMSS(s){return(s-(s%=60))/60+(9<s?':':':0')+s}
做. . 该函数接受一个数字(首选)或一个字符串(2转换'惩罚'，你可以通过在函数调用的参数s中前置+来减半，如:fmtMSS(+strSeconds))，表示正整数秒s作为参数。
例子:
fmtMSS( 0 ); // 0:00
fmtMSS( '8'); // 0:08
fmtMSS( 9 ); // 0:09
fmtMSS( '10'); // 0:10
fmtMSS( 59 ); // 0:59
fmtMSS( +'60'); // 1:00
fmtMSS( 69 ); // 1:09
fmtMSS( 3599 ); // 59:59
fmtMSS('3600'); // 60:00
fmtMSS('3661'); // 61:01
fmtMSS( 7425 ); // 123:45
分解:
function fmtMSS(s){ // accepts seconds as Number or String. Returns m:ss
return( s - // take value s and subtract (will try to convert String to Number)
( s %= 60 ) // the new value of s, now holding the remainder of s divided by 60
// (will also try to convert String to Number)
) / 60 + ( // and divide the resulting Number by 60
// (can never result in a fractional value = no need for rounding)
// to which we concatenate a String (converts the Number to String)
// who's reference is chosen by the conditional operator:
9 < s // if seconds is larger than 9
? ':' // then we don't need to prepend a zero
: ':0' // else we do need to prepend a zero
) + s ; // and we add Number s to the string (converting it to String as well)
}
注意:负数范围可以通过在返回表达式前加上(0>s?(s=-s，'-'): ")+来增加(实际上，(0>s?(s=-s，'-'):0)+也可以)。
function formatSeconds(s: number) {
let minutes = ~~(s / 60);
let seconds = ~~(s % 60);
return minutes + ':' + seconds;
}
试试这个: 将秒转换为小时，分钟和秒。
function convertTime(sec) {
var hours = Math.floor(sec/3600);
(hours >= 1) ? sec = sec - (hours*3600) : hours = '00';
var min = Math.floor(sec/60);
(min >= 1) ? sec = sec - (min*60) : min = '00';
(sec < 1) ? sec='00' : void 0;
(min.toString().length == 1) ? min = '0'+min : void 0;
(sec.toString().length == 1) ? sec = '0'+sec : void 0;
return hours+':'+min+':'+sec;
}
我在想一个更快的方法来完成这件事，这就是我想到的
var sec = parseInt(time);
var min=0;
while(sec>59){ sec-=60; min++;}
如果我们想要将“时间”转换为分钟和秒，例如:
// time = 75,3 sec
var sec = parseInt(time); //sec = 75
var min=0;
while(sec>59){ sec-=60; min++;} //sec = 15; min = 1
Var秒= 60; var measuredTime =新的日期(空); measuredTime.setSeconds(秒);//指定SECONDS的值 var Time = measuredTime.toISOString()。8 substr(11日); . getelementbyid (id1”)。value =时间; < div class = "形式的班级”> <label for="course" class="col-md-4">Time</label> . < div class = " col-md-8”> <input type="text" class="form-control" id="id1" name="field">最小值 < / div > < / div >
