function main()
{
Hello();
}
function Hello()
{
// How do you find out the caller function is 'main'?
}
有办法找到调用堆栈吗?
function main()
{
Hello();
}
function Hello()
{
// How do you find out the caller function is 'main'?
}
有办法找到调用堆栈吗?
当前回答
只需控制台日志错误堆栈。这样你就可以知道你是如何被召唤的
Const hello = () => { console.log(新的错误('I was called').stack) } Const sello = () => { 你好() } 你可以()
其他回答
试试下面的代码:
function getStackTrace(){
var f = arguments.callee;
var ret = [];
var item = {};
var iter = 0;
while ( f = f.caller ){
// Initialize
item = {
name: f.name || null,
args: [], // Empty array = no arguments passed
callback: f
};
// Function arguments
if ( f.arguments ){
for ( iter = 0; iter<f.arguments.length; iter++ ){
item.args[iter] = f.arguments[iter];
}
} else {
item.args = null; // null = argument listing not supported
}
ret.push( item );
}
return ret;
}
在火狐21和Chromium-25里为我工作过。
我知道你提到了“在Javascript中”,但如果目的是调试,我认为使用浏览器的开发工具更容易。这是它在Chrome中的样子: 只需将调试器放置在您想要研究堆栈的位置。
我认为下面的代码段可能会有帮助:
window.fnPureLog = function(sStatement, anyVariable) {
if (arguments.length < 1) {
throw new Error('Arguments sStatement and anyVariable are expected');
}
if (typeof sStatement !== 'string') {
throw new Error('The type of sStatement is not match, please use string');
}
var oCallStackTrack = new Error();
console.log(oCallStackTrack.stack.replace('Error', 'Call Stack:'), '\n' + sStatement + ':', anyVariable);
}
执行以下代码:
window.fnPureLog = function(sStatement, anyVariable) {
if (arguments.length < 1) {
throw new Error('Arguments sStatement and anyVariable are expected');
}
if (typeof sStatement !== 'string') {
throw new Error('The type of sStatement is not match, please use string');
}
var oCallStackTrack = new Error();
console.log(oCallStackTrack.stack.replace('Error', 'Call Stack:'), '\n' + sStatement + ':', anyVariable);
}
function fnBsnCallStack1() {
fnPureLog('Stock Count', 100)
}
function fnBsnCallStack2() {
fnBsnCallStack1()
}
fnBsnCallStack2();
日志是这样的:
Call Stack:
at window.fnPureLog (<anonymous>:8:27)
at fnBsnCallStack1 (<anonymous>:13:5)
at fnBsnCallStack2 (<anonymous>:17:5)
at <anonymous>:20:1
Stock Count: 100
在这里,除了函数名之外的所有内容都被RegExp从caller.toString()中剥离。
<!DOCTYPE html>
<meta charset="UTF-8">
<title>Show the callers name</title><!-- This validates as html5! -->
<script>
main();
function main() { Hello(); }
function Hello(){
var name = Hello.caller.toString().replace(/\s\([^#]+$|^[^\s]+\s/g,'');
name = name.replace(/\s/g,'');
if ( typeof window[name] !== 'function' )
alert ("sorry, the type of "+name+" is "+ typeof window[name]);
else
alert ("The name of the "+typeof window[name]+" that called is "+name);
}
</script>
为什么上面所有的解决方案看起来都像火箭科学。同时,它不应该比这段代码更复杂。都要归功于这个家伙
如何在JavaScript中找到调用者函数?
var stackTrace = function() {
var calls = [];
var caller = arguments.callee.caller;
for (var k = 0; k < 10; k++) {
if (caller) {
calls.push(caller);
caller = caller.caller;
}
}
return calls;
};
// when I call this inside specific method I see list of references to source method, obviously, I can add toString() to each call to see only function's content
// [function(), function(data), function(res), function(l), function(a, c), x(a, b, c, d), function(c, e)]