意大利:

>>> import locale
>>> locale.setlocale(locale.LC_ALL,"")
'Italian_Italy.1252'
>>> f"{1000:n}"
'1.000'

这里有一个也适用于浮动:

def float2comma(f):
    s = str(abs(f)) # Convert to a string
    decimalposition = s.find(".") # Look for decimal point
    if decimalposition == -1:
        decimalposition = len(s) # If no decimal, then just work from the end
    out = "" 
    for i in range(decimalposition+1, len(s)): # do the decimal
        if not (i-decimalposition-1) % 3 and i-decimalposition-1: out = out+","
        out = out+s[i]      
    if len(out):
        out = "."+out # add the decimal point if necessary
    for i in range(decimalposition-1,-1,-1): # working backwards from decimal point
        if not (decimalposition-i-1) % 3 and decimalposition-i-1: out = ","+out
        out = s[i]+out      
    if f < 0:
        out = "-"+out
    return out

使用的例子:

>>> float2comma(10000.1111)
'10,000.111,1'
>>> float2comma(656565.122)
'656,565.122'
>>> float2comma(-656565.122)
'-656,565.122'

这是烘焙到python per PEP -> https://www.python.org/dev/peps/pep-0378/

只需使用format(1000， '，d')来显示一个带千位分隔符的整数

PEP中描述了更多的格式，请尝试一下

在低效率和不可读性方面，它是很难被击败的:

>>> import itertools
>>> s = '-1234567'
>>> ','.join(["%s%s%s" % (x[0], x[1] or '', x[2] or '') for x in itertools.izip_longest(s[::-1][::3], s[::-1][1::3], s[::-1][2::3])])[::-1].replace('-,','-')

意大利:

>>> import locale
>>> locale.setlocale(locale.LC_ALL,"")
'Italian_Italy.1252'
>>> f"{1000:n}"
'1.000'

下面是一些格式化的方法(与float和int类型兼容)

num = 2437.68

# Way 1: String Formatting

'{:,}'.format(num)
>>> '2,437.68'


# Way 2: F-Strings

f'{num:,}'
>>> '2,437.68'


# Way 3: Built-in Format Function

format(num, ',')
>>> '2,437.68'