浮点数:

float(filter(lambda x: x!=',', '1,234.52'))
# returns 1234.52

对于整数：

int(filter(lambda x: x!=',', '1,234'))
# returns 1234

在浮点数中同时使用分隔符和小数: (在这个例子中，小数点后两位)

large_number = 4545454.26262666
print(f"Formatted: {large_number:,.2f}")

结果: 格式:4545454点

这里有一个也适用于浮动:

def float2comma(f):
    s = str(abs(f)) # Convert to a string
    decimalposition = s.find(".") # Look for decimal point
    if decimalposition == -1:
        decimalposition = len(s) # If no decimal, then just work from the end
    out = "" 
    for i in range(decimalposition+1, len(s)): # do the decimal
        if not (i-decimalposition-1) % 3 and i-decimalposition-1: out = out+","
        out = out+s[i]      
    if len(out):
        out = "."+out # add the decimal point if necessary
    for i in range(decimalposition-1,-1,-1): # working backwards from decimal point
        if not (decimalposition-i-1) % 3 and decimalposition-i-1: out = ","+out
        out = s[i]+out      
    if f < 0:
        out = "-"+out
    return out

使用的例子:

>>> float2comma(10000.1111)
'10,000.111,1'
>>> float2comma(656565.122)
'656,565.122'
>>> float2comma(-656565.122)
'-656,565.122'

你也可以使用'{:n}'。区域设置表示的格式(值)。我认为这是最简单的现场解决方案。

有关更多信息，请在Python DOC中搜索数千个。

对于货币，可以使用locale。货币，设置标志分组:

Code

import locale

locale.setlocale( locale.LC_ALL, '' )
locale.currency( 1234567.89, grouping = True )

输出

'Portuguese_Brazil.1252'
'R$ 1.234.567,89'

浮点数:

float(filter(lambda x: x!=',', '1,234.52'))
# returns 1234.52

对于整数：

int(filter(lambda x: x!=',', '1,234'))
# returns 1234

我有这个代码的python 2和python 3版本。我知道这个问题是关于python2的，但是现在(8年过去了，哈哈)人们可能会使用python3。Python 3代码:

import random
number = str(random.randint(1, 10000000))
comma_placement = 4
print('The original number is: {}. '.format(number))
while True:
    if len(number) % 3 == 0:
        for i in range(0, len(number) // 3 - 1):
            number = number[0:len(number) - comma_placement + 1] + ',' + number[len(number) - comma_placement + 1:]
            comma_placement = comma_placement + 4
    else:
        for i in range(0, len(number) // 3):
            number = number[0:len(number) - comma_placement + 1] + ',' + number[len(number) - comma_placement + 1:]
    break
print('The new and improved number is: {}'.format(number))        

Python 2代码:(编辑。python代码不能工作。我认为语法是不同的)。

import random
number = str(random.randint(1, 10000000))
comma_placement = 4
print 'The original number is: %s.' % (number)
while True:
    if len(number) % 3 == 0:
        for i in range(0, len(number) // 3 - 1):
            number = number[0:len(number) - comma_placement + 1] + ',' + number[len(number) - comma_placement + 1:]
            comma_placement = comma_placement + 4
    else:
        for i in range(0, len(number) // 3):
            number = number[0:len(number) - comma_placement + 1] + ',' + number[len(number) - comma_placement + 1:]
    break
print 'The new and improved number is: %s.' % (number)