我正在寻找一种方法来取代字符在一个Swift字符串。
示例:“This is my string”
我想用“+”替换“”以获得“This+is+my+string”。
我怎样才能做到这一点呢?
我正在寻找一种方法来取代字符在一个Swift字符串。
示例:“This is my string”
我想用“+”替换“”以获得“This+is+my+string”。
我怎样才能做到这一点呢?
当前回答
很少发生在我身上,我只是想改变字符串中的(一个单词或字符)
所以我用了字典
extension String{
func replace(_ dictionary: [String: String]) -> String{
var result = String()
var i = -1
for (of , with): (String, String)in dictionary{
i += 1
if i<1{
result = self.replacingOccurrences(of: of, with: with)
}else{
result = result.replacingOccurrences(of: of, with: with)
}
}
return result
}
}
使用
let mobile = "+1 (800) 444-9999"
let dictionary = ["+": "00", " ": "", "(": "", ")": "", "-": ""]
let mobileResult = mobile.replace(dictionary)
print(mobileResult) // 001800444999
其他回答
var str = "This is my string"
str = str.replacingOccurrences(of: " ", with: "+")
print(str)
一个快速的解决方案沿着Sunkas的路线:
extension String {
mutating func replace(_ originalString:String, with newString:String) {
self = self.replacingOccurrences(of: originalString, with: newString)
}
}
Use:
var string = "foo!"
string.replace("!", with: "?")
print(string)
输出:
foo?
var str = "This is my string"
print(str.replacingOccurrences(of: " ", with: "+"))
输出是
This+is+my+string
迅速扩展:
extension String {
func stringByReplacing(replaceStrings set: [String], with: String) -> String {
var stringObject = self
for string in set {
stringObject = self.stringByReplacingOccurrencesOfString(string, withString: with)
}
return stringObject
}
}
继续使用let replacedString = yorString。stringbyreplacement (replaceStrings: [" ","?","."],加上:“+”)
函数的速度是我几乎不能感到骄傲的,但是你可以在一次传递一个String数组来进行多次替换。
斯威夫特5.5
我正在使用这个扩展:
extension String {
func replaceCharacters(characters: String, toSeparator: String) -> String {
let characterSet = CharacterSet(charactersIn: characters)
let components = components(separatedBy: characterSet)
let result = components.joined(separator: toSeparator)
return result
}
func wipeCharacters(characters: String) -> String {
return self.replaceCharacters(characters: characters, toSeparator: "")
}
}
用法:
"<34353 43434>".replaceCharacters(characters: "< >", toSeparator:"+") // +34353+43434+
"<34353 43434>".wipeCharacters(characters: "< >") // 3435343434