我使用以下JavaScript代码打开了一个网络摄像头:

const stream = await navigator.mediaDevices.getUserMedia({ /* ... */ });

是否有任何JavaScript代码停止或关闭网络摄像头?


当前回答

不要使用stream.stop(),它已被弃用

MediaStream用法

使用stream.getTracks()。forEach(track => track.stop())

其他回答

您可以直接使用成功处理程序中返回给getUserMedia的流对象来结束流。如。

localMediaStream.stop()

视频。Src =""或null只会从视频标签中删除源。它不会释放硬件。

启动和停止网络摄像头,(更新2020 React es6)

开启Web摄像头

stopWebCamera =()=>

       //Start Web Came
      if (navigator.mediaDevices && navigator.mediaDevices.getUserMedia) {
        //use WebCam
        navigator.mediaDevices.getUserMedia({ video: true }).then(stream => {
          this.localStream = stream;
          this.video.srcObject = stream;
          this.video.play();
        });
      }
 }

停止网络摄像头或视频播放一般

stopVideo =()=>
{
        this.video.pause();
        this.video.src = "";
        this.video.srcObject = null;

         // As per new API stop all streams
        if (this.localStream)
          this.localStream.getTracks().forEach(track => track.stop());
}

停止网络摄像头功能,即使视频流:

  this.video.src = this.state.videoToTest;
  this.video.play();

有溪流形式成功的参考吗

var streamRef;

var handleVideo = function (stream) {
    streamRef = stream;
}

//this will stop video and audio both track
streamRef.getTracks().map(function (val) {
    val.stop();
});

试试下面的方法:

var mediaStream = null;
    navigator.getUserMedia(
        {
            audio: true,
            video: true
        },
        function (stream) {
            mediaStream = stream;
            mediaStream.stop = function () {
                this.getAudioTracks().forEach(function (track) {
                    track.stop();
                });
                this.getVideoTracks().forEach(function (track) { //in case... :)
                    track.stop();
                });
            };
            /*
             * Rest of your code.....
             * */
        });

    /*
    * somewhere insdie your code you call
    * */
    mediaStream.stop();

不要使用stream.stop(),它已被弃用

MediaStream用法

使用stream.getTracks()。forEach(track => track.stop())