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2025-01-06 08:00:05

Parcelable遇到IOException写入序列化对象getactivity()

所以我在logcat中得到这个:

java.lang.RuntimeException: Parcelable encountered IOException writing serializable object (name = com.resources.student_list.Student)

我知道这意味着我的学生类是不可序列化的，但它是，这是我的学生类:

import java.io.Serializable;


public class Student implements Comparable<Student>,  Serializable{

    private static final long serialVersionUID = 1L;
    private String firstName, lastName;
    private DSLL<Grade> gradeList; 

    public Student() {
        firstName = "";
        lastName = "";
        gradeList = new DSLL<Grade>();
    }

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    public String getLastName() {
        return lastName;
    }

    public void setLastName(String lastName) {
        this.lastName = lastName;
    }

    public DSLL<Grade> getGradeList() {
        return gradeList;
    }

    public void setGradeList(DSLL<Grade> gradeList) {
        this.gradeList = gradeList;
    }

    public int compareTo(Student arg0) {
        return this.lastName.compareTo(arg0.getLastName());
    }

}

这是使用getIntent()方法的代码:

public void onItemClick(AdapterView<?> parent, View viewClicked, int pos,
                                long id) {

                            Student clickedStudent = studentList.get(pos);
                            int position = pos;
                            Intent intent = new Intent(getActivity().getApplicationContext(), ShowStudentActivity.class);
                            Log.e("CINTENT","CREATED!!!");
                            intent.putExtra("clickedStudent",clickedStudent);
                            intent.putExtra("newStudentList",newStudentList);
                            intent.putExtra("position",position);
                            Log.e("putExtra","Passed");
                            Log.e("Start activity","passed");
                            startActivity(intent);

                        } 

                    });

请帮我弄清楚这是怎么回事。

这是整个LogCat:

04-17 16:12:28.890: E/AndroidRuntime(22815): FATAL EXCEPTION: main
04-17 16:12:28.890: E/AndroidRuntime(22815): java.lang.RuntimeException: Parcelable encountered IOException writing serializable object (name = com.resources.student_list.Student)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Parcel.writeSerializable(Parcel.java:1181)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Parcel.writeValue(Parcel.java:1135)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Parcel.writeMapInternal(Parcel.java:493)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Bundle.writeToParcel(Bundle.java:1612)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Parcel.writeBundle(Parcel.java:507)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.content.Intent.writeToParcel(Intent.java:6111)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.app.ActivityManagerProxy.startActivity(ActivityManagerNative.java:1613)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.app.Instrumentation.execStartActivity(Instrumentation.java:1422)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.app.Activity.startActivityForResult(Activity.java:3191)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.support.v4.app.FragmentActivity.startActivityFromFragment(FragmentActivity.java:848)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.support.v4.app.Fragment.startActivity(Fragment.java:878)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at com.example.student_lists.MainActivity$DummySectionFragment$2.onItemClick(MainActivity.java:477)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.widget.AdapterView.performItemClick(AdapterView.java:292)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.widget.AbsListView.performItemClick(AbsListView.java:1058)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.widget.AbsListView$PerformClick.run(AbsListView.java:2514)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.widget.AbsListView$1.run(AbsListView.java:3168)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Handler.handleCallback(Handler.java:605)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Handler.dispatchMessage(Handler.java:92)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Looper.loop(Looper.java:137)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.app.ActivityThread.main(ActivityThread.java:4447)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.lang.reflect.Method.invokeNative(Native Method)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.lang.reflect.Method.invoke(Method.java:511)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at dalvik.system.NativeStart.main(Native Method)
04-17 16:12:28.890: E/AndroidRuntime(22815): Caused by: java.io.NotSerializableException: com.resources.student_list.DSLL$DNode
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1364)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeFieldValues(ObjectOutputStream.java:979)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.defaultWriteObject(ObjectOutputStream.java:368)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeHierarchy(ObjectOutputStream.java:1074)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1404)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeFieldValues(ObjectOutputStream.java:979)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.defaultWriteObject(ObjectOutputStream.java:368)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeHierarchy(ObjectOutputStream.java:1074)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1404)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
04-17 16:12:28.890: E/AndroidRuntime(22815):    at android.os.Parcel.writeSerializable(Parcel.java:1176)

Caused by: java.io.NotSerializableException: com.resources.student_list.DSLL$DNode

您的DSLL类似乎有一个DNode静态内部类，而DNode是不可序列化的。

2014-04-17 20:43:36

我也阶段这些错误，我是一点点改变在modelClass，这是实现Serializable接口，如:

在这个Model类中，还使用writeToParcel()重写方法实现了Parcelable接口

然后就得到了错误的“create creator”，所以creator是写的，也是用模型类的构造函数创建的，有参数和没有参数。

       @Override
        public void writeToParcel(Parcel dest, int flags) {
            dest.writeString(id);
            dest.writeString(name);
        }

        protected ArtistTrackClass(Parcel in) {
            id = in.readString();
            name = in.readString();
        }

       public ArtistTrackClass() {

        }

    public static final Creator<ArtistTrackClass> CREATOR = new Creator<ArtistTrackClass>() {
        @Override
        public ArtistTrackClass createFromParcel(Parcel in) {
            return new ArtistTrackClass(in);
        }

        @Override
        public ArtistTrackClass[] newArray(int size) {
            return new ArtistTrackClass[size];
        }
    };

在这里,

ArtistTrackClass ->模式

带有Parcel参数的构造函数是"read our attributes" writeToParcel()是"write our attributes"

2016-03-10 05:15:08

如果不能使DNode可序列化，一个好的解决方案是在变量中添加“transient”。

例子:

public static transient DNode dNode = null;

这将在使用Intent.putExtra(…)时忽略变量。

2016-07-22 15:53:44

问题发生时，你的自定义类有属性一些其他类。“位图”。我所做的是将属性字段从“私有Bitmap photo”更改为“私有transient Bitmap photo”。然而，当我在接收活动中获得tent()后，图像是空的。正因为如此，我将自定义类传递给意图，并且我已经从图像中创建了一个字节数组，并将其单独传递给意图:

selectedItem是我的自定义对象getplacphoto是他获取图像的方法。我之前已经设置了它，现在我只是先得到它，然后转换它并分别传递它:

 Bitmap image = selectedItem.getPlacePhoto();
 image.compress(Bitmap.CompressFormat.PNG, 100, stream);
 byte[] byteArray = stream.toByteArray();
 Intent intent = new Intent(YourPresentActivity.this, 
 TheReceiverActivity.class);
 intent.putExtra("selectedItem", selectedItem);                 
 intent.putExtra("image", byteArray);
 startActivity(intent);

`

然后在接收器活动中，我得到我的对象和图像作为字节数组，解码图像并将其设置为我的对象作为照片属性。

 Intent intent = getIntent();
 selectedItem = (ListItem) intent.getSerializableExtra("selectedItem");
 byte[] byteArray = getIntent().getByteArrayExtra("image");
 Bitmap image = BitmapFactory.decodeByteArray(byteArray, 0, 
 byteArray.length);
 selectedItem.setPhoto(image);
2017-06-07 17:08:47

Grade类也必须实现Serializable

public class Grade implements Serializable {
.....your content....
}
2017-09-23 19:27:03

你的OneThread类也应该实现Serializable。所有子类和内部子类必须实现Serializable。

这对我来说很管用……

2017-11-01 10:50:54

对我来说，这是通过使类中的变量瞬态解决的。

代码:

public class UserLocation implements Serializable {
   public Location lastKnownLocation;
   public UserLocation() {}
}

代码后

public class UserLocation implements Serializable {
    public transient Location lastKnownLocation;
    public UserLocation() {}
}
2018-01-19 05:35:28

需要在bean类中将所有数组列表更改为Serializable wif:

public static class PremiumListBean  implements Serializable {
    private List<AddOnValueBean> AddOnValue;

    public List<AddOnValueBean> getAddOnValue() {
        return AddOnValue;
     }

    public void setAddOnValue(List<AddOnValueBean> AddOnValue) {
        this.AddOnValue = AddOnValue;
    }


    public static class AddOnValueBean  implements Serializable{

        @SerializedName("Premium")
        private String Premium;

        public String getPremium() {
            return Premium;
        }

        public void setPremium(String Premium) {
            this.Premium = Premium;
        }
    }
 }
2019-03-14 12:41:14

如果你的POJO包含任何其他模型，也应该实现Serializable

2019-03-21 11:12:11

发生异常的原因是任何内部类或其他引用类都没有实现可序列化的实现。因此，请确保所有引用的类都必须实现可序列化的实现。

2019-05-29 09:40:01

我遇到了同样的问题，问题是有一些内部类与静态关键字。删除static关键字后，它开始工作，而且内部类应该实现为Serializable

问题场景

class A implements Serializable{ 
  class static B{
  } 
}

解决了

class A implements Serializable{ 
      class B implements Serializable{
      } 
    }
2019-07-04 20:40:42

在我的情况下，我必须实现MainActivity为Serializable太。因为我需要从MainActivity启动一个服务:

public class MainActivity extends AppCompatActivity implements Serializable {
    ...
    musicCover = new MusicCover(); // A Serializable Object
    ...
    sIntent = new Intent(MainActivity.this, MusicPlayerService.class);
    sIntent.setAction(MusicPlayerService.ACTION_INITIALIZE_COVER);
    sIntent.putExtra(MusicPlayerService.EXTRA_COVER, musicCover);
    startService(sIntent);
}
2019-08-16 14:43:56

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