我有对象数组person (int age;字符串名称;)。
我如何按名字的字母顺序排序这个数组,然后按年龄?
你会用哪种算法呢?
我有对象数组person (int age;字符串名称;)。
我如何按名字的字母顺序排序这个数组,然后按年龄?
你会用哪种算法呢?
当前回答
根据需要创建尽可能多的比较器。之后,为每个订单类别调用“then comparison”方法。这是Streams的一种做法。看到的:
//Sort by first and last name
System.out.println("\n2.Sort list of person objects by firstName then "
+ "by lastName then by age");
Comparator<Person> sortByFirstName
= (p, o) -> p.firstName.compareToIgnoreCase(o.firstName);
Comparator<Person> sortByLastName
= (p, o) -> p.lastName.compareToIgnoreCase(o.lastName);
Comparator<Person> sortByAge
= (p, o) -> Integer.compare(p.age,o.age);
//Sort by first Name then Sort by last name then sort by age
personList.stream().sorted(
sortByFirstName
.thenComparing(sortByLastName)
.thenComparing(sortByAge)
).forEach(person->
System.out.println(person));
在多个字段上对用户定义的对象进行排序- Comparator (lambda stream)
其他回答
我不确定在Person类中写比较器是否丑陋。是这样的:
public class Person implements Comparable <Person> {
private String lastName;
private String firstName;
private int age;
public Person(String firstName, String lastName, int BirthDay) {
this.firstName = firstName;
this.lastName = lastName;
this.age = BirthDay;
}
public int getAge() {
return age;
}
public String getFirstName() {
return firstName;
}
public String getLastName() {
return lastName;
}
@Override
public int compareTo(Person o) {
// default compareTo
}
@Override
public String toString() {
return firstName + " " + lastName + " " + age + "";
}
public static class firstNameComperator implements Comparator<Person> {
@Override
public int compare(Person o1, Person o2) {
return o1.firstName.compareTo(o2.firstName);
}
}
public static class lastNameComperator implements Comparator<Person> {
@Override
public int compare(Person o1, Person o2) {
return o1.lastName.compareTo(o2.lastName);
}
}
public static class ageComperator implements Comparator<Person> {
@Override
public int compare(Person o1, Person o2) {
return o1.age - o2.age;
}
}
}
public class Test {
private static void print() {
ArrayList<Person> list = new ArrayList();
list.add(new Person("Diana", "Agron", 31));
list.add(new Person("Kay", "Panabaker", 27));
list.add(new Person("Lucy", "Hale", 28));
list.add(new Person("Ashley", "Benson", 28));
list.add(new Person("Megan", "Park", 31));
list.add(new Person("Lucas", "Till", 27));
list.add(new Person("Nicholas", "Hoult", 28));
list.add(new Person("Aly", "Michalka", 28));
list.add(new Person("Adam", "Brody", 38));
list.add(new Person("Chris", "Pine", 37));
Collections.sort(list, new Person.lastNameComperator());
Iterator<Person> it = list.iterator();
while(it.hasNext())
System.out.println(it.next().toString());
}
}
使用Comparator,然后将对象放入Collection,然后Collections.sort();
class Person {
String fname;
String lname;
int age;
public Person() {
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getFname() {
return fname;
}
public void setFname(String fname) {
this.fname = fname;
}
public String getLname() {
return lname;
}
public void setLname(String lname) {
this.lname = lname;
}
public Person(String fname, String lname, int age) {
this.fname = fname;
this.lname = lname;
this.age = age;
}
@Override
public String toString() {
return fname + "," + lname + "," + age;
}
}
public class Main{
public static void main(String[] args) {
List<Person> persons = new java.util.ArrayList<Person>();
persons.add(new Person("abc3", "def3", 10));
persons.add(new Person("abc2", "def2", 32));
persons.add(new Person("abc1", "def1", 65));
persons.add(new Person("abc4", "def4", 10));
System.out.println(persons);
Collections.sort(persons, new Comparator<Person>() {
@Override
public int compare(Person t, Person t1) {
return t.getAge() - t1.getAge();
}
});
System.out.println(persons);
}
}
你可以这样做:
List<User> users = Lists.newArrayList(
new User("Pedro", 12),
new User("Maria", 10),
new User("Rafael",12)
);
users.sort(
Comparator.comparing(User::getName).thenComparing(User::getAge)
);
您可以使用通用串行比较器按多个字段对集合进行排序。
import org.apache.commons.lang3.reflect.FieldUtils;
import java.util.Arrays;
import java.util.Comparator;
import java.util.List;
/**
* @author MaheshRPM
*/
public class SerialComparator<T> implements Comparator<T> {
List<String> sortingFields;
public SerialComparator(List<String> sortingFields) {
this.sortingFields = sortingFields;
}
public SerialComparator(String... sortingFields) {
this.sortingFields = Arrays.asList(sortingFields);
}
@Override
public int compare(T o1, T o2) {
int result = 0;
try {
for (String sortingField : sortingFields) {
if (result == 0) {
Object value1 = FieldUtils.readField(o1, sortingField, true);
Object value2 = FieldUtils.readField(o2, sortingField, true);
if (value1 instanceof Comparable && value2 instanceof Comparable) {
Comparable comparable1 = (Comparable) value1;
Comparable comparable2 = (Comparable) value2;
result = comparable1.compareTo(comparable2);
} else {
throw new RuntimeException("Cannot compare non Comparable fields. " + value1.getClass()
.getName() + " must implement Comparable<" + value1.getClass().getName() + ">");
}
} else {
break;
}
}
} catch (IllegalAccessException e) {
throw new RuntimeException(e);
}
return result;
}
}
当使用Guava的ComparisonChain时,我会很小心,因为它会为每个被比较的元素创建一个实例,所以如果你在排序,你会看到N x Log N个比较链的创建,或者如果你在迭代和检查相等,则会有N个实例。
如果可能的话,我会使用最新的Java 8 API或Guava的ordered API创建一个静态比较器,这里是Java 8的一个例子:
import java.util.Comparator;
import static java.util.Comparator.naturalOrder;
import static java.util.Comparator.nullsLast;
private static final Comparator<Person> COMPARATOR = Comparator
.comparing(Person::getName, nullsLast(naturalOrder()))
.thenComparingInt(Person::getAge);
@Override
public int compareTo(@NotNull Person other) {
return COMPARATOR.compare(this, other);
}
以下是如何使用番石榴的订购API: https://github.com/google/guava/wiki/OrderingExplained