是否有一种方法，例如，打印Hello World!每n秒? 例如，程序将遍历我所拥有的任何代码，然后在5秒后(使用time.sleep())执行该代码。我会用这个来更新文件，而不是打印Hello World。
例如:
startrepeat("print('Hello World')", .01) # Repeats print('Hello World') ever .01 seconds
for i in range(5):
print(i)
>> Hello World!
>> 0
>> 1
>> 2
>> Hello World!
>> 3
>> Hello World!
>> 4
当前回答
import threading
def printit():
threading.Timer(5.0, printit).start()
print "Hello, World!"
printit()
# continue with the rest of your code
https://docs.python.org/3/library/threading.html#timer-objects
其他回答
你可以启动一个单独的线程，它的唯一职责是数5秒，更新文件，重复。您不希望这个单独的线程干扰主线程。
def update():
import time
while True:
print 'Hello World!'
time.sleep(5)
它会作为函数运行。while True:让它永远运行。如果需要，你可以把它从函数中提出来。
下面是一个不需要每n秒创建一个新线程的版本:
from threading import Event, Thread
def call_repeatedly(interval, func, *args):
stopped = Event()
def loop():
while not stopped.wait(interval): # the first call is in `interval` secs
func(*args)
Thread(target=loop).start()
return stopped.set
该事件用于停止重复:
cancel_future_calls = call_repeatedly(5, print, "Hello, World")
# do something else here...
cancel_future_calls() # stop future calls
请参见改进setInterval python的当前实现
为自己省下一次精神分裂发作，使用高级Python调度器: http://pythonhosted.org/APScheduler
代码非常简单:
from apscheduler.scheduler import Scheduler
sched = Scheduler()
sched.start()
def some_job():
print "Every 10 seconds"
sched.add_interval_job(some_job, seconds = 10)
....
sched.shutdown()
import threading
def printit():
threading.Timer(5.0, printit).start()
print "Hello, World!"
printit()
# continue with the rest of your code
https://docs.python.org/3/library/threading.html#timer-objects
