我有一个表，上面列出了人们的出生日期(目前是nvarchar(25))
我如何将其转换为日期，然后以年为单位计算他们的年龄?
我的数据如下所示
ID Name DOB
1 John 1992-01-09 00:00:00
2 Sally 1959-05-20 00:00:00
我希望看到:
ID Name AGE DOB
1 John 17 1992-01-09 00:00:00
2 Sally 50 1959-05-20 00:00:00
当前回答
CREATE function dbo.AgeAtDate(
@DOB datetime,
@CompareDate datetime
)
returns INT
as
begin
return CASE WHEN @DOB is null
THEN
null
ELSE
DateDiff(yy,@DOB, @CompareDate)
- CASE WHEN datepart(mm,@CompareDate) > datepart(mm,@DOB) OR (datepart(mm,@CompareDate) = datepart(mm,@DOB) AND datepart(dd,@CompareDate) >= datepart(dd,@DOB))
THEN 0
ELSE 1
END
END
End
GO
其他回答
这个怎么样:
SET @Age = CAST(DATEDIFF(Year, @DOB, @Stamp) as int)
IF (CAST(DATEDIFF(DAY, DATEADD(Year, @Age, @DOB), @Stamp) as int) < 0)
SET @Age = @Age - 1
这将正确地处理生日和舍入的问题:
DECLARE @dob datetime
SET @dob='1992-01-09 00:00:00'
SELECT DATEDIFF(YEAR, '0:0', getdate()-@dob)
select floor((datediff(day,0,@today) - datediff(day,0,@birthdate)) / 365.2425) as age
这里有很多365.25的答案。记住闰年是如何定义的:
每四年一次 除了每100年 除了每400年
CREATE function dbo.AgeAtDate(
@DOB datetime,
@CompareDate datetime
)
returns INT
as
begin
return CASE WHEN @DOB is null
THEN
null
ELSE
DateDiff(yy,@DOB, @CompareDate)
- CASE WHEN datepart(mm,@CompareDate) > datepart(mm,@DOB) OR (datepart(mm,@CompareDate) = datepart(mm,@DOB) AND datepart(dd,@CompareDate) >= datepart(dd,@DOB))
THEN 0
ELSE 1
END
END
End
GO
DECLARE @yourBirthDate DATETIME = '1987-05-25'
SELECT YEAR(DATEADD(DAY, DATEDIFF(DAY, @yourBirthDate, GETDATE()), CAST('0001-01-01' AS DATETIME2))) - 1
