可以构建的最小bash循环(基于ghostdog74答案)

for dir in directory/*                                                     
do                                                                                 
  echo ${dir}                                                                  
done

按目录压缩一大堆文件

for dir in directory/*
do
  zip -r ${dir##*/} ${dir}
done                                               

找到。-type d -maxdepth

处理包含空格的目录

灵感来自Sorpigal

while IFS= read -d $'\0' -r file ; do 
    echo $file; ls $file ; 
done < <(find /path/to/dir/ -mindepth 1 -maxdepth 1 -type d -print0)

原帖(不适用空格)

灵感来自Boldewyn:使用find命令的循环示例。

for D in $(find /path/to/dir/ -mindepth 1 -maxdepth 1 -type d) ; do
    echo $D ;
done

cd /tmp
find . -maxdepth 1 -mindepth 1 -type d -printf '%f\n'

简单解释一下:

find finds files (quite obviously) . is the current directory, which after the cd is /tmp (IMHO this is more flexible than having /tmp directly in the find command. You have only one place, the cd, to change, if you want more actions to take place in this folder) -maxdepth 1 and -mindepth 1 make sure that find only looks in the current directory and doesn't include . itself in the result -type d looks only for directories -printf '%f\n prints only the found folder's name (plus a newline) for each hit.

就是这样!

到目前为止，所有答案都使用find，这里有一个只有外壳的答案。在您的情况下不需要外部工具:

for dir in /tmp/*/     # list directories in the form "/tmp/dirname/"
do
    dir=${dir%*/}      # remove the trailing "/"
    echo "${dir##*/}"    # print everything after the final "/"
done

find . -mindepth 1 -maxdepth 1 -type d -printf "%P\n"