如何做URL解码在Java?

在Java中，我想转换这个:

https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest_type

https://mywebsite/docs/english/site/mybook.do&request_type

这是我目前所拥有的:

class StringUTF 
{
    public static void main(String[] args) 
    {
        try{
            String url = 
               "https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do" +
               "%3Frequest_type%3D%26type%3Dprivate";

            System.out.println(url+"Hello World!------->" +
                new String(url.getBytes("UTF-8"),"ASCII"));
        }
        catch(Exception E){
        }
    }
}

但这并不正确。这些%3A和%2F格式被称为什么?我如何转换它们?

当前回答

使用java.net.URI类:

public String getDecodedURL(String encodedUrl) {
    try {
        URI uri = new URI(encodedUrl);
        return uri.getScheme() + ":" + uri.getSchemeSpecificPart();
    } catch (Exception e) {
        return "";
    }
}

请注意，异常处理可以做得更好，但这与本例没有太大关系。

2020-04-14 13:20:26

其他回答

public String decodeString(String URL)
    {

    String urlString="";
    try {
        urlString = URLDecoder.decode(URL,"UTF-8");
        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block

        }

        return urlString;

    }

2015-06-16 07:12:51

%3A和%2F是URL编码字符。使用下面的java代码将它们转换回:和/

String decoded = java.net.URLDecoder.decode(url, "UTF-8");

2011-05-26 12:03:49

这个问题之前已经回答过了(尽管这个问题是第一个!):

“你应该使用java.net.URI来做这件事，因为URLDecoder类做的是x-www-form-urlencoded解码，这是错误的(尽管它的名字，它是为表单数据)。”

如URL类文档所述:

管理url编码和解码的建议方法是使用URI，并使用toURI()和在这两个类之间进行转换 URI.toURL()。 URLEncoder和URLDecoder类也可以使用，但仅用于 HTML表单编码，这与编码方案不同在RFC2396中定义。

基本上:

String url = "https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest_type";
System.out.println(new java.net.URI(url).getPath());

会给你:

https://mywebsite/docs/english/site/mybook.do?request_type

2013-05-09 03:07:54

使用java.net.URI类:

public String getDecodedURL(String encodedUrl) {
    try {
        URI uri = new URI(encodedUrl);
        return uri.getScheme() + ":" + uri.getSchemeSpecificPart();
    } catch (Exception e) {
        return "";
    }
}

请注意，异常处理可以做得更好，但这与本例没有太大关系。

2020-04-14 13:20:26

import java.io.UnsupportedEncodingException;
import java.net.URISyntaxException;

public class URLDecoding { 

    String decoded = "";

    public String decodeMethod(String url) throws UnsupportedEncodingException
    {
        decoded = java.net.URLDecoder.decode(url, "UTF-8"); 
        return  decoded;
//"You should use java.net.URI to do this, as the URLDecoder class does x-www-form-urlencoded decoding which is wrong (despite the name, it's for form data)."
    }

    public String getPathMethod(String url) throws URISyntaxException 
    {
        decoded = new java.net.URI(url).getPath();  
        return  decoded; 
    }

    public static void main(String[] args) throws UnsupportedEncodingException, URISyntaxException 
    {
        System.out.println(" Here is your Decoded url with decode method : "+ new URLDecoding().decodeMethod("https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest_type")); 
        System.out.println("Here is your Decoded url with getPath method : "+ new URLDecoding().getPathMethod("https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest")); 

    } 

}

你可以明智地选择你的方法:)

2014-06-05 06:35:45

如何做URL解码在Java?

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