如何做URL解码在Java?

在Java中，我想转换这个:

https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest_type

https://mywebsite/docs/english/site/mybook.do&request_type

这是我目前所拥有的:

class StringUTF 
{
    public static void main(String[] args) 
    {
        try{
            String url = 
               "https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do" +
               "%3Frequest_type%3D%26type%3Dprivate";

            System.out.println(url+"Hello World!------->" +
                new String(url.getBytes("UTF-8"),"ASCII"));
        }
        catch(Exception E){
        }
    }
}

但这并不正确。这些%3A和%2F格式被称为什么?我如何转换它们?

当前回答

你得到的字符串是application/x-www-form-urlencoded编码。

使用URLDecoder将其转换为Java字符串。

URLDecoder.decode( url, "UTF-8" );

2011-05-26 12:02:41

其他回答

你得到的字符串是application/x-www-form-urlencoded编码。

使用URLDecoder将其转换为Java字符串。

URLDecoder.decode( url, "UTF-8" );

2011-05-26 12:02:41

这与UTF-8或ASCII等字符编码没有任何关系。这里的字符串是URL编码的。这种编码与字符编码完全不同。

试试这样做:

try {
    String result = java.net.URLDecoder.decode(url, StandardCharsets.UTF_8.name());
} catch (UnsupportedEncodingException e) {
    // not going to happen - value came from JDK's own StandardCharsets
}

Java 10在API中增加了对Charset的直接支持，这意味着不需要捕获UnsupportedEncodingException:

String result = java.net.URLDecoder.decode(url, StandardCharsets.UTF_8);

注意，字符编码(如UTF-8或ASCII)决定字符到原始字节的映射。有关字符编码的介绍，请参阅本文。

2011-05-26 12:04:19

我也有这个问题，来这里寻求答案。但是我用了那个问题被批准的朋友的代码，没用。我尝试了一些不同的方法，并且成功了，所以我分享了下面的代码行，以防它有所帮助。

URLDecoder.decode(URLDecoder.decode(url, StandardCharsets.UTF_8)))

2022-09-30 11:42:13

如果它是整数值，我们也必须捕获NumberFormatException。

try {
        Integer result = Integer.valueOf(URLDecoder.decode(urlNumber, "UTF-8"));
    } catch (NumberFormatException | UnsupportedEncodingException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

2021-05-30 12:42:35

import java.io.UnsupportedEncodingException;
import java.net.URISyntaxException;

public class URLDecoding { 

    String decoded = "";

    public String decodeMethod(String url) throws UnsupportedEncodingException
    {
        decoded = java.net.URLDecoder.decode(url, "UTF-8"); 
        return  decoded;
//"You should use java.net.URI to do this, as the URLDecoder class does x-www-form-urlencoded decoding which is wrong (despite the name, it's for form data)."
    }

    public String getPathMethod(String url) throws URISyntaxException 
    {
        decoded = new java.net.URI(url).getPath();  
        return  decoded; 
    }

    public static void main(String[] args) throws UnsupportedEncodingException, URISyntaxException 
    {
        System.out.println(" Here is your Decoded url with decode method : "+ new URLDecoding().decodeMethod("https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest_type")); 
        System.out.println("Here is your Decoded url with getPath method : "+ new URLDecoding().getPathMethod("https%3A%2F%2Fmywebsite%2Fdocs%2Fenglish%2Fsite%2Fmybook.do%3Frequest")); 

    } 

}

你可以明智地选择你的方法:)

2014-06-05 06:35:45

如何做URL解码在Java?

推荐文章

最新文章

标签