捕获输出如下的异常:
Traceback (most recent call last):
File "c:/tmp.py", line 1, in <module>
4 / 0
ZeroDivisionError: integer division or modulo by zero
我想把它格式化为:
ZeroDivisonError, tmp.py, 1
捕获输出如下的异常:
Traceback (most recent call last):
File "c:/tmp.py", line 1, in <module>
4 / 0
ZeroDivisionError: integer division or modulo by zero
我想把它格式化为:
ZeroDivisonError, tmp.py, 1
当前回答
你可以在不导入traceback的情况下实现这一点:
try:
func1()
except Exception as ex:
trace = []
tb = ex.__traceback__
while tb is not None:
trace.append({
"filename": tb.tb_frame.f_code.co_filename,
"name": tb.tb_frame.f_code.co_name,
"lineno": tb.tb_lineno
})
tb = tb.tb_next
print(str({
'type': type(ex).__name__,
'message': str(ex),
'trace': trace
}))
输出:
{
'type': 'ZeroDivisionError',
'message': 'division by zero',
'trace': [
{
'filename': '/var/playground/main.py',
'name': '<module>',
'lineno': 16
},
{
'filename': '/var/playground/main.py',
'name': 'func1',
'lineno': 11
},
{
'filename': '/var/playground/main.py',
'name': 'func2',
'lineno': 7
},
{
'filename': '/var/playground/my.py',
'name': 'test',
'lineno': 2
}
]
}
其他回答
下面是一个显示发生异常的行号的示例。
import sys
try:
print(5/0)
except Exception as e:
print('Error on line {}'.format(sys.exc_info()[-1].tb_lineno), type(e).__name__, e)
print('And the rest of program continues')
这是我用来获取文件名的。
__file__.__str__
总之,我创建了一个页面来显示错误。返回此异常。
context={
'details':'Type of error:{}:Function name:{}:Line number:{}'.format(exc_type, fname, exc_tb.tb_lineno),
'error_details':str(e),
'filename':__file__.__str__,
})
发生异常时的情况:
import sys, os
try:
raise NotImplementedError("No error")
except Exception as e:
exc_type, exc_obj, exc_tb = sys.exc_info()
fname = os.path.split(exc_tb.tb_frame.f_code.co_filename)[1]
print(exc_type, fname, exc_tb.tb_lineno)
你可以在不导入traceback的情况下实现这一点:
try:
func1()
except Exception as ex:
trace = []
tb = ex.__traceback__
while tb is not None:
trace.append({
"filename": tb.tb_frame.f_code.co_filename,
"name": tb.tb_frame.f_code.co_name,
"lineno": tb.tb_lineno
})
tb = tb.tb_next
print(str({
'type': type(ex).__name__,
'message': str(ex),
'trace': trace
}))
输出:
{
'type': 'ZeroDivisionError',
'message': 'division by zero',
'trace': [
{
'filename': '/var/playground/main.py',
'name': '<module>',
'lineno': 16
},
{
'filename': '/var/playground/main.py',
'name': 'func1',
'lineno': 11
},
{
'filename': '/var/playground/main.py',
'name': 'func2',
'lineno': 7
},
{
'filename': '/var/playground/my.py',
'name': 'test',
'lineno': 2
}
]
}
traceback.format_exception()的源代码(Py v2.7.3)和调用的/相关函数有很大帮助。令人尴尬的是,我总是忘记阅读原文。我只是在徒劳地搜索了类似的细节后才这样做的。一个简单的问题,“如何为异常重新创建与Python相同的输出,并具有所有相同的细节?”这将使任何人得到90%以上的他们想要的东西。沮丧的我想出了这个例子。我希望它能帮助其他人。(它确实帮助了我!: -)
import sys, traceback
traceback_template = '''Traceback (most recent call last):
File "%(filename)s", line %(lineno)s, in %(name)s
%(type)s: %(message)s\n''' # Skipping the "actual line" item
# Also note: we don't walk all the way through the frame stack in this example
# see hg.python.org/cpython/file/8dffb76faacc/Lib/traceback.py#l280
# (Imagine if the 1/0, below, were replaced by a call to test() which did 1/0.)
try:
1/0
except:
# http://docs.python.org/2/library/sys.html#sys.exc_info
exc_type, exc_value, exc_traceback = sys.exc_info() # most recent (if any) by default
'''
Reason this _can_ be bad: If an (unhandled) exception happens AFTER this,
or if we do not delete the labels on (not much) older versions of Py, the
reference we created can linger.
traceback.format_exc/print_exc do this very thing, BUT note this creates a
temp scope within the function.
'''
traceback_details = {
'filename': exc_traceback.tb_frame.f_code.co_filename,
'lineno' : exc_traceback.tb_lineno,
'name' : exc_traceback.tb_frame.f_code.co_name,
'type' : exc_type.__name__,
'message' : exc_value.message, # or see traceback._some_str()
}
del(exc_type, exc_value, exc_traceback) # So we don't leave our local labels/objects dangling
# This still isn't "completely safe", though!
# "Best (recommended) practice: replace all exc_type, exc_value, exc_traceback
# with sys.exc_info()[0], sys.exc_info()[1], sys.exc_info()[2]
print
print traceback.format_exc()
print
print traceback_template % traceback_details
print
具体回答此问题:
sys.exc_info()[0].__name__, os.path.basename(sys.exc_info()[2].tb_frame.f_code.co_filename), sys.exc_info()[2].tb_lineno