在python3中，你可以使用pathlib模块(pathlib. python)。例如PurePath):

>>> import pathlib

>>> path = pathlib.PurePath('/folderA/folderB/folderC/folderD/')
>>> path.name
'folderD'

如果您想要文件所在的最后一个文件夹名称:

>>> path = pathlib.PurePath('/folderA/folderB/folderC/folderD/file.py')
>>> path.parent.name
'folderD'

以下是我的方法:

>>> import os
>>> print os.path.basename(
        os.path.dirname('/folderA/folderB/folderC/folderD/test.py'))
folderD
>>> print os.path.basename(
        os.path.dirname('/folderA/folderB/folderC/folderD/'))
folderD
>>> print os.path.basename(
        os.path.dirname('/folderA/folderB/folderC/folderD'))
folderC

在python3中，你可以使用pathlib模块(pathlib. python)。例如PurePath):

>>> import pathlib

>>> path = pathlib.PurePath('/folderA/folderB/folderC/folderD/')
>>> path.name
'folderD'

如果您想要文件所在的最后一个文件夹名称:

>>> path = pathlib.PurePath('/folderA/folderB/folderC/folderD/file.py')
>>> path.parent.name
'folderD'

你可以这样做

>>> import os
>>> os.path.basename('/folderA/folderB/folderC/folderD')

UPDATE1:如果你给它/folderA/folderB/folderC/folderD/xx.py，这种方法是有效的。这将xx.py作为基名。我猜这不是你想要的。所以你可以这样做-

>>> import os
>>> path = "/folderA/folderB/folderC/folderD"
>>> if os.path.isdir(path):
        dirname = os.path.basename(path)

UPDATE2:正如lars指出的那样，进行更改以适应以'/'结尾。

>>> from os.path import normpath, basename
>>> basename(normpath('/folderA/folderB/folderC/folderD/'))
'folderD'

如果你使用本地python包pathlib，它真的很简单。

>>> from pathlib import Path
>>> your_path = Path("/folderA/folderB/folderC/folderD/")
>>> your_path.stem
'folderD'

假设在文件夹d中有一个文件的路径。

>>> from pathlib import Path
>>> your_path = Path("/folderA/folderB/folderC/folderD/file.txt")
>>> your_path.name
'file.txt'
>>> your_path.parent
'folderD'

我喜欢Path的部分方法:

grandparent_directory, parent_directory, filename = Path(export_filename).parts[-3:]
log.info(f'{t: <30}: {num_rows: >7} Rows exported to {grandparent_directory}/{parent_directory}/{filename}')