是否可以使用Selenium WebDriver进行截图?

(注:不含硒遥控器)


当前回答

Python

您可以使用Python web驱动程序从windows中捕获图像。使用下面的代码哪个页面需要捕获屏幕截图。

driver.save_screenshot('c:\foldername\filename.extension(png, jpeg)')

其他回答

你可以使用Webdriverclass对象创建一个webdriver支持的selenium对象,然后你可以截屏。

Ruby

time = Time.now.strftime('%a_%e_%Y_%l_%m_%p_%M_%S')
file_path = File.expand_path(File.dirname(__FILE__) + 'screens_shot')+'/'+time +'.png'
#driver.save_screenshot(file_path)
page.driver.browser.save_screenshot file_path

你可以在浏览器中截取网页可见部分的截图:

首先导入:

import java.io.File;
import com.google.common.io.Files;

Then

File src=((TakesScreenshot)driver).getScreenShotAs(OutputType.FILE);
Files.copy(src,new File("new path/pic.jpeg"));

另外,在Selenium4之后,你还可以截取webelement的截图:

WebElement element=driver.findElement(By.xpath("xpath 
 here"));
File src=element.getScreenShotAs(OutputType.FILE);
File.copy(src,new File("new path/pic.jpeg"));

Java

对于较新版本的Java, FileUtils函数不起作用。在这里,下面的功能可以完美地复制屏幕截图。

import java.io.File;
import org.openqa.selenium.OutputType;
import org.openqa.selenium.TakesScreenshot;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.io.FileHandler;

File scrFile = ((TakesScreenshot)driver).getScreenshotAs(OutputType.FILE);
File destfile = new File(destination folder /filename.extension);
FileHandler.copy(scrfile, destfile);
/**
 * Take a screenshot and move to the given folder location.
 *
 * @param driver
 * @param folderLocation
 * @return screenShotFilePath
 */
public static String captureScreenshot(WebDriver driver, String folderLocation) {

    // Variable to store screenshot's file path.
    String screenShotFilePath = null;

    // Generate unique id for screen shot name.
    String uniqueId = UUID.randomUUID().toString().substring(31);

    if (driver != null) {

        // Generate screenshot as a file
        File scrFile = ((TakesScreenshot) driver).getScreenshotAs(OutputType.FILE);

        // New screenshot file path with having file name
        screenShotFilePath = folderLocation + File.separator + uniqueId + ".png";

        // Move file to the destination location.
        FileUtils.moveFile(scrFile, new File(screenShotFilePath));
    }

    return screenShotFilePath;
}