我想在一个网站的页脚放一个版权声明,但我认为这对于过时的年份来说是非常俗气的。
如何在php4或php5中自动更新年份?
我想在一个网站的页脚放一个版权声明,但我认为这对于过时的年份来说是非常俗气的。
如何在php4或php5中自动更新年份?
当前回答
以我为例,wordpress网站页脚的版权声明需要更新。
想法很简单,但涉及的步骤比预期的要多。
Open footer.php in your theme's folder. Locate copyright text, expected this to be all hard coded but found: <div id="copyright"> <?php the_field('copyright_disclaimer', 'options'); ?> </div> Now we know the year is written somewhere in WordPress admin so locate that to delete the year written text. In WP-Admin, go to Options on the left main admin menu: Then on next page go to the tab Disclaimers: and near the top you will find Copyright year: DELETE the © symbol + year + the empty space following the year, then save your page with Update button at top-right of page. With text version of year now delete, we can go and add our year that updates automatically with PHP. Go back to chunk of code in STEP 2 found in footer.php and update that to this: <div id="copyright"> ©<?php echo date("Y"); ?> <?php the_field('copyright_disclaimer', 'options'); ?> </div> Done! Just need to test to ensure changes have taken effect as expected.
这对很多人来说可能不是同样的情况,但是我们在相当多的客户站点中遇到过这种模式,并且认为最好在这里记录。
其他回答
这个给出了当地时间:
$year = date('Y'); // 2008
这个UTC:
$year = gmdate('Y'); // 2008
我的超级懒惰版本显示版权行,自动保持更新:
© <?php
$copyYear = 2008;
$curYear = date('Y');
echo $copyYear . (($copyYear != $curYear) ? '-' . $curYear : '');
?> Me, Inc.
今年(2008年),它会说:
©2008 Me, Inc
明年,它会说:
©2008-2009 Me, Inc
并且永远保持当前年份的更新。
或者(PHP 5.3.0+)一种使用匿名函数的紧凑方法,这样你就不会有变量泄露,也不会重复代码/常量:
©
<?php call_user_func(function($y){$c=date('Y');echo $y.(($y!=$c)?'-'.$c:'');}, 2008); ?>
Me, Inc.
我显示版权的方式,它会自动更新
<p class="text-muted credit">Copyright ©
<?php
$copyYear = 2017; // Set your website start date
$curYear = date('Y'); // Keeps the second year updated
echo $copyYear . (($copyYear != $curYear) ? '-' . $curYear : '');
?>
</p>
它将输出结果为
copyright @ 2017 //if $copyYear is 2017
copyright @ 2017-201x //if $copyYear is not equal to Current Year.
使用PHP函数date()。
它接受当前日期,然后你给它提供一个格式
格式是Y,大写的Y是四位数的年份。
<?php echo date("Y"); ?>
对于4位数表示:
<?php echo date('Y'); ?>
2位数表示:
<?php echo date('y'); ?>
查看php文档了解更多信息: https://secure.php.net/manual/en/function.date.php