我需要在JavaScript中做一个HTTP GET请求。最好的方法是什么?
我需要在Mac OS X的dashcode小部件中做到这一点。
我需要在JavaScript中做一个HTTP GET请求。最好的方法是什么?
我需要在Mac OS X的dashcode小部件中做到这一点。
当前回答
没有回调的版本
var i = document.createElement("img");
i.src = "/your/GET/url?params=here";
其他回答
一个复制粘贴的现代版本(使用fetch和箭头函数):
//Option with catch
fetch( textURL )
.then(async r=> console.log(await r.text()))
.catch(e=>console.error('Boo...' + e));
//No fear...
(async () =>
console.log(
(await (await fetch( jsonURL )).json())
)
)();
复制粘贴的经典版本:
let request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (this.readyState === 4) {
if (this.status === 200) {
document.body.className = 'ok';
console.log(this.responseText);
} else if (this.response == null && this.status === 0) {
document.body.className = 'error offline';
console.log("The computer appears to be offline.");
} else {
document.body.className = 'error';
}
}
};
request.open("GET", url, true);
request.send(null);
jQuery:
$.get(
"somepage.php",
{paramOne : 1, paramX : 'abc'},
function(data) {
alert('page content: ' + data);
}
);
你也可以用纯JS来做:
// Create the XHR object.
function createCORSRequest(method, url) {
var xhr = new XMLHttpRequest();
if ("withCredentials" in xhr) {
// XHR for Chrome/Firefox/Opera/Safari.
xhr.open(method, url, true);
} else if (typeof XDomainRequest != "undefined") {
// XDomainRequest for IE.
xhr = new XDomainRequest();
xhr.open(method, url);
} else {
// CORS not supported.
xhr = null;
}
return xhr;
}
// Make the actual CORS request.
function makeCorsRequest() {
// This is a sample server that supports CORS.
var url = 'http://html5rocks-cors.s3-website-us-east-1.amazonaws.com/index.html';
var xhr = createCORSRequest('GET', url);
if (!xhr) {
alert('CORS not supported');
return;
}
// Response handlers.
xhr.onload = function() {
var text = xhr.responseText;
alert('Response from CORS request to ' + url + ': ' + text);
};
xhr.onerror = function() {
alert('Woops, there was an error making the request.');
};
xhr.send();
}
详见:html5rocks教程
简单的异步请求:
function get(url, callback) {
var getRequest = new XMLHttpRequest();
getRequest.open("get", url, true);
getRequest.addEventListener("readystatechange", function() {
if (getRequest.readyState === 4 && getRequest.status === 200) {
callback(getRequest.responseText);
}
});
getRequest.send();
}
短的、干净的:
const http = new XMLHttpRequest() http。打开(“得到”,“https://api.lyrics.ovh/v1/toto/africa”) http.send () http。onload = () => console.log(http.response)