改变

fieldname?: any[]; 

:

fieldname?: any; 

你也可以添加@ts-ignore来使编译器只在这种情况下静音:

//@ts-ignore
makes: any[];

这是因为typescript 2.7.2包含了严格的类检查，其中所有属性都应该在构造函数中声明。所以要解决这个问题，只需添加一个感叹号(!)，比如:

name!:string;

一个更好的方法是在变量的末尾加上感叹号，因为你确定它不是undefined或null，例如你正在使用一个ElementRef，需要从模板加载，不能在构造函数中定义，做如下所示的事情

class Component {
 ViewChild('idname') variable! : ElementRef;
}

这个已经在Angular Github的https://github.com/angular/angular/issues/24571上讨论过了

我认为这是每个人都会转向的方向

引用自https://github.com/angular/angular/issues/24571#issuecomment-404606595

For angular components, use the following rules in deciding between:
a) adding initializer
b) make the field optional
c) leave the '!'

If the field is annotated with @input - Make the field optional b) or add an initializer a).
If the input is required for the component user - add an assertion in ngOnInit and apply c.
If the field is annotated @ViewChild, @ContentChild - Make the field optional b).
If the field is annotated with @ViewChildren or @ContentChildren - Add back '!' - c).
Fields that have an initializer, but it lives in ngOnInit. - Move the initializer to the constructor.
Fields that have an initializer, but it lives in ngOnInit and cannot be moved because it depends on other @input fields - Add back '!' - c).

你可以在构造函数中这样声明属性:

export class Test {
constructor(myText:string) {
this.myText= myText;
} 

myText: string ;
}