在我正在处理的提取中,我有2个datetime列。一列存储日期,另一列存储如下所示的时间。
如何查询表,将这两个字段组合成类型为datetime的1列?
日期
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
次
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000
在我正在处理的提取中,我有2个datetime列。一列存储日期,另一列存储如下所示的时间。
如何查询表,将这两个字段组合成类型为datetime的1列?
日期
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
次
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000
当前回答
如果你没有使用SQL Server 2008(即你只有一个DateTime数据类型),你可以使用以下(承认粗糙和准备就绪)TSQL来实现你想要的:
DECLARE @DateOnly AS datetime
DECLARE @TimeOnly AS datetime
SET @DateOnly = '07 aug 2009 00:00:00'
SET @TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, @DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, @TimeOnly), @TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, @DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, @TimeOnly), @TimeOnly)
as datetime)
虽然粗糙,但很管用!
其他回答
如果你没有使用SQL Server 2008(即你只有一个DateTime数据类型),你可以使用以下(承认粗糙和准备就绪)TSQL来实现你想要的:
DECLARE @DateOnly AS datetime
DECLARE @TimeOnly AS datetime
SET @DateOnly = '07 aug 2009 00:00:00'
SET @TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, @DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, @TimeOnly), @TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, @DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, @TimeOnly), @TimeOnly)
as datetime)
虽然粗糙,但很管用!
select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between @FromDate and @ToDate
SELECT (CAST(@TimeField As Date) As DateTime) + CAST(CAST(@TimeField As Time) As DateTime)
找到这个工作的两个日期,你想从一个日期和日期从另一个:
declare @Time as datetime = '2021-11-19 12:34'
declare @Date as datetime = '2021-10-10'
SELECT @time + datediff(day, @Time, @Date)
如果两个字段都是datetime,那么简单地添加它们就可以了。 例如: 声明@d datetime, @t datetime Set @d = '2009-03-12 00:00:00.000'; Set @t = ' 189-12-30 12:30:00.000'; 选择@d + @t 如果您使用Date & Time数据类型,则只需将时间转换为datetime 例如: 声明@d日期,@t时间 Set @d = '2009-03-12'; Set @t = '12:30:00.000'; 选择@d + cast(@t as datetime)