如果你没有使用SQL Server 2008(即你只有一个DateTime数据类型)，你可以使用以下(承认粗糙和准备就绪)TSQL来实现你想要的:

DECLARE @DateOnly AS datetime
DECLARE @TimeOnly AS datetime 

SET @DateOnly = '07 aug 2009 00:00:00'
SET @TimeOnly = '01 jan 1899 10:11:23'


-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, @DateOnly))

-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, @TimeOnly), @TimeOnly)

-- Concatenates Date and Time parts.
SELECT
CAST(
    DATEADD(dd, 0, DATEDIFF(dd, 0, @DateOnly)) + ' ' +
    DATEADD(Day, -DATEDIFF(Day, 0, @TimeOnly), @TimeOnly)           
as datetime)

虽然粗糙，但很管用!

SELECT (CAST(@TimeField As Date) As DateTime) + CAST(CAST(@TimeField As Time) As DateTime)

另一种方法是使用CONCATand CAST，请注意，需要使用DATETIME2(x)才能使其工作。你可以将x设置为0- 7,7之间的任何值，这意味着没有精度损失。

DECLARE @date date = '2018-03-12'
DECLARE @time time = '07:00:00.0000000'
SELECT CAST(CONCAT(@date, ' ', @time) AS DATETIME2(7))

返回2018-03-12 07:00:00.0000000

在SQL Server 14上测试

如上所述，我有很多错误，所以我这样做

try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime

这对我很管用。

这对我很有效

CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)

(适用于SQL 2008 R2)

这是我的解决方案，它忽略了时间列的日期值

CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)

希望这能帮助到其他人