这是一个从表中选择所有记录的示例代码。有人能告诉我如何选择该表的最后一条记录吗?

select * from table

当我使用:选择*从表顺序由ID DESC限制 第1行:'LIMIT'附近的语法不正确。 这是我使用的代码:

private void LastRecord()
{
    SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["HELPDESK_OUTLOOKConnectionString3"].ToString());

    conn.Open();
    SqlDataReader myReader = null;
    SqlCommand myCommand = new SqlCommand("SELECT * FROM HD_AANVRAGEN ORDER BY " +
                "aanvraag_id DESC LIMIT 1", conn);
    myReader = myCommand.ExecuteReader();
    while (myReader.Read())
    {
        TextBox1.Text = (myReader["aanvraag_id"].ToString());
        TextBox1.Text += (myReader["wijziging_nummer"].ToString());
        TextBox1.Text += (myReader["melding_id"].ToString());
        TextBox1.Text += (myReader["aanvraag_titel"].ToString());
        TextBox1.Text += (myReader["aanvraag_omschrijving"].ToString());
        TextBox1.Text += (myReader["doorlooptijd_id"].ToString());
        TextBox1.Text += (myReader["rapporteren"].ToString());
        TextBox1.Text += (myReader["werknemer_id"].ToString());
        TextBox1.Text += (myReader["outlook_id"].ToString());
    }
}

当前回答

要获取sql数据库的最后一行,请使用以下sql字符串:

SELECT * FROM TableName WHERE id=(SELECT max(id) FROM TableName);

输出:

最后一行你的数据库!

其他回答

SELECT * FROM TABLE ORDER BY ID DESC LIMIT 1

是的,这是mysql, SQL Server:

SELECT TOP 1 * FROM Table ORDER BY ID DESC

MS SQL Server已经支持ANSI SQL FETCH FIRST很多年了:

SELECT * FROM TABLE
ORDER BY ID DESC 
OFFSET 0 ROWS FETCH FIRST 1 ROW ONLY

(适用于大多数现代数据库。)

你也可以这样做:

SELECT LAST (column_name) AS LAST_CUSTOMER FROM table_name

select ADU.itemid, ADU.startdate, internalcostprice 
from ADUITEMINTERNALCOSTPRICE ADU

right join

   (select max(STARTDATE) as Max_date, itemid 
   from ADUITEMINTERNALCOSTPRICE
   group by itemid) as A

on A.ITEMID = ADU.ITEMID
and startdate= Max_date
$sql="SELECT tot_visit FROM visitors WHERE date = DATE(NOW()) - 1 into @s                
$conn->query($sql);
$sql = "INSERT INTO visitors (nbvisit_day,date,tot_visit) VALUES (1,CURRENT_DATE,@s+1)";
$conn->query($sql);