试试这个，这将正确创建您的对象

 $result = mysql_query("SELECT ...");
 $rows = array();
   while($r = mysql_fetch_assoc($result)) {
     $rows['object_name'][] = $r;
   }

 print json_encode($rows);

使用FOR循环的另一个选项:

 $sth = mysql_query("SELECT ...");
 for($rows = array(); $row = mysql_fetch_assoc($sth); $rows[] = $row);
 print json_encode($rows);

唯一的缺点是循环for比while或特别是foreach慢

试试这个，这将正确创建您的对象

 $result = mysql_query("SELECT ...");
 $rows = array();
   while($r = mysql_fetch_assoc($result)) {
     $rows['object_name'][] = $r;
   }

 print json_encode($rows);

if ($result->num_rows > 0) {
    # code...
    $arr = [];
    $inc = 0;
    while ($row = $result->fetch_assoc()) {
        # code...
        $jsonArrayObject = (array('lat' => $row["lat"], 'lon' => $row["lon"], 'addr' => $row["address"]));
        $arr[$inc] = $jsonArrayObject;
        $inc++;
    }
    $json_array = json_encode($arr);
    echo $json_array;
} else {
    echo "0 results";
}

根据我的经验，在命名根元素之前，上述方法是行不通的 数组中的东西，我还没有能够访问任何东西 最后的json。

$sth = mysql_query("SELECT ...");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
    $rows['root_name'] = $r;
}
print json_encode($rows);

这应该能奏效!

下面的代码在这里可以正常工作!

<?php

  $con=mysqli_connect("localhost",$username,$password,databaseName);

  // Check connection
  if (mysqli_connect_errno())
  {
   echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

  $query = "the query here";

  $result = mysqli_query($con,$query);

  $rows = array();
  while($r = mysqli_fetch_array($result)) {
    $rows[] = $r;
  }
  echo json_encode($rows);

  mysqli_close($con);
?>