寻找返回目录中最新文件的命令。

没有看到ls的limit参数…


当前回答

基于dmckee回答的简短变体:

ls -t | head -1

其他回答

假设您不关心以a开头的隐藏文件。

ls -rt | tail -n 1

否则

ls -Art | tail -n 1

找到前缀为shravan*的文件并查看

less $(ls -Art shravan* | tail -n 1)

这是一个递归版本(即,它在某个目录或其任何子目录中查找最近更新的文件)

find /dir/path -type f -printf "%T@ %p\n" | sort -n | cut -d' ' -f 2- | tail -n 1

命令行简单的外行解释:

find /dir/path -type f finds all the files in the directory -printf "%T@ %p\n" prints a line for each file where %T@ is the float seconds since 1970 epoch and %p is the filename path and \n is the new line character for more info see man find | is a shell pipe (see man bash section on Pipelines) sort -n means to sort on the first column and to treat the token as numerical instead of lexicographic (see man sort) cut -d' ' -f 2- means to split each line using the character and then to print all tokens starting at the second token (see man cut) NOTE: -f 2 would print only the second token tail -n 1 means to print the last line (see man tail)

ls -t | head -n1

这个命令实际上给出了当前工作目录中最新修改的文件或目录。

递归地:

find $1 -type f -exec stat --format '%Y :%y %n' "{}" \; | sort -nr | cut -d: -f2- | head