寻找返回目录中最新文件的命令。

没有看到ls的limit参数…


当前回答

使用R递归选项..你可以认为这是对好的答案的增强

ls -arRtlh | tail -50

其他回答

ls -lAtr | tail -1

其他解决方案不包括以“。”开头的文件。

该命令还包括'。'和'..,这可能是也可能不是你想要的:

Ls -latr | tail -1

这是一个递归版本(即,它在某个目录或其任何子目录中查找最近更新的文件)

find /dir/path -type f -printf "%T@ %p\n" | sort -n | cut -d' ' -f 2- | tail -n 1

命令行简单的外行解释:

find /dir/path -type f finds all the files in the directory -printf "%T@ %p\n" prints a line for each file where %T@ is the float seconds since 1970 epoch and %p is the filename path and \n is the new line character for more info see man find | is a shell pipe (see man bash section on Pipelines) sort -n means to sort on the first column and to treat the token as numerical instead of lexicographic (see man sort) cut -d' ' -f 2- means to split each line using the character and then to print all tokens starting at the second token (see man cut) NOTE: -f 2 would print only the second token tail -n 1 means to print the last line (see man tail)

递归地:

find $1 -type f -exec stat --format '%Y :%y %n' "{}" \; | sort -nr | cut -d: -f2- | head

所有这些ls/tail解决方案都非常适用于目录中的文件—忽略子目录。

为了在搜索中包含所有文件(递归地),可以使用find。Gioele建议对格式化的查找输出进行排序。但是要小心使用空格(他的建议不适用于空格)。

这应该适用于所有文件名:

find $DIR -type f -printf "%T@ %p\n" | sort -n | sed -r 's/^[0-9.]+\s+//' | tail -n 1 | xargs -I{} ls -l "{}"

这一分类由时,见人发现:

%Ak    File's  last  access  time in the format specified by k, which is either `@' or a directive for the C `strftime' function.  The possible values for k are listed below; some of them might not be available on all systems, due to differences in `strftime' between systems.
       @      seconds since Jan. 1, 1970, 00:00 GMT, with fractional part.
%Ck    File's last status change time in the format specified by k, which is the same as for %A.
%Tk    File's last modification time in the format specified by k, which is the same as for %A.

用%C替换%T,按ctime排序。

如果你想获得最近修改的文件,也包括任何子目录,你可以用这个小的联机程序:

find . -type f -exec stat -c '%Y %n' {} \; | sort -nr | awk -v var="1" 'NR==1,NR==var {print $0}' | while read t f; do d=$(date -d @$t "+%b %d %T %Y"); echo "$d -- $f"; done

如果你想对已更改的文件做同样的事情,但对于已访问的文件,你只需更改

参数%Y从stat命令到%X。对于最近访问的文件,你的命令是这样的:

find . -type f -exec stat -c '%X %n' {} \; | sort -nr | awk -v var="1" 'NR==1,NR==var {print $0}' | while read t f; do d=$(date -d @$t "+%b %d %T %Y"); echo "$d -- $f"; done

对于这两个命令,如果您想列出多个文件,还可以更改var="1"参数。