A Simple find can work handy. alias it in your ~/.bashrc 文件:

alias ffind find / -type f | xargs grep

开始一个新的终端和问题:

ffind 'text-to-find-here'

下面的命令将为此做得很好:

find ./ -name "file_pattern_name"  -exec grep -r "pattern" {} \;

避免混乱并安装 ack-grep. 它消除了许多许可和引用问题。

apt-get install ack-grep

然后转到您想要搜索的目录,并运行下面的命令。

cd /
ack-grep "find my keyword"

要搜索字符串和输出,就是与搜索字符串相同的字符串:

for i in $(find /path/of/target/directory -type f); do grep -i "the string to look for" "$i"; done

吉:

for i in $(find /usr/share/applications -type f); \
do grep -i "web browser" "$i"; done

要显示包含搜索字符串的文件名:

for i in $(find /path/of/target/directory -type f); do if grep -i "the string to look for" "$i" > /dev/null; then echo "$i"; fi; done;

吉:

for i in $(find /usr/share/applications -type f); \
do if grep -i "web browser" "$i" > /dev/null; then echo "$i"; \
fi; done;

你可以使用:

grep -r "string to be searched"  /path/to/dir

r 是可重复的,因此将在指定的路径和其子指南中进行搜索,这将告诉您文件名以及在文件中印刷线的字符串。

或类似于您正在尝试的命令(例如: )在所有JavaScript文件中搜索( (*.js):

find . -name '*.js' -exec grep -i 'string to search for' {} \; -print

这将打印文本显示的文件中的行,但它不会打印文件名。

除了此命令之外,我们还可以写下: grep -rn “String to search” /path/to/directory/or/file -r: recursive search n: line number will be shown for matches

find /path -type f -exec grep -l "string" {} \;

评论的解释

查找是一个命令,允许您在特定路径的子目录中找到文件和其他对象,如目录和链接,如果您不指定该文件名称应满足的面具,则列出所有目录对象。

-type f specifies that it should proceed only files, not directories etc.
-exec grep specifies that for every found file, it should run grep command, passing its filename as an argument to it, by replacing {} with the filename