我有一组数字，我需要确保它们是唯一的。我在互联网上找到了下面的代码片段，它工作得很好，直到数组中有一个零。我在Stack Overflow上找到了另一个脚本，看起来几乎与它完全一样，但它不会失败。
所以为了帮助我学习，有人能帮我确定原型脚本哪里出错吗？
Array.prototype.getUnique = function() {
var o = {}, a = [], i, e;
for (i = 0; e = this[i]; i++) {o[e] = 1};
for (e in o) {a.push (e)};
return a;
}
重复问题的更多答案：
从JS数组中删除重复值
类似的问题：
获取数组中的所有非唯一值（即：重复/多次出现）
当前回答
使用对象键创建唯一数组，我尝试了以下操作
function uniqueArray( ar ) {
var j = {};
ar.forEach( function(v) {
j[v+ '::' + typeof v] = v;
});
return Object.keys(j).map(function(v){
return j[v];
});
}
uniqueArray(["1",1,2,3,4,1,"foo", false, false, null,1]);
它返回[“1”，1，2，3，4，“foo”，false，null]
其他回答
对于字符串数组：
function removeDuplicatesFromArray(arr) {
const unique = {};
arr.forEach((word) => {
unique[word] = 1; // it doesn't really matter what goes here
});
return Object.keys(unique);
}
使用lodash和identity lambda函数执行，只需在使用对象之前定义它
const _ = require('lodash');
...
_.uniqBy([{a:1,b:2},{a:1,b:2},{a:1,b:3}], v=>v.a.toString()+v.b.toString())
_.uniq([1,2,3,3,'a','a','x'])
并且将具有：
[{a:1,b:2},{a:1,b:3}]
[1,2,3,'a','x']
（这是最简单的方法）
Array.prototype.getUnique = function() {
var o = {}, a = []
for (var i = 0; i < this.length; i++) o[this[i]] = 1
for (var e in o) a.push(e)
return a
}
这个不是纯的，它会修改数组，但这是最快的。如果你的速度更快，请写下评论；）
http://jsperf.com/unique-array-webdeb
Array.prototype.uniq = function(){
for(var i = 0, l = this.length; i < l; ++i){
var item = this[i];
var duplicateIdx = this.indexOf(item, i + 1);
while(duplicateIdx != -1) {
this.splice(duplicateIdx, 1);
duplicateIdx = this.indexOf(item, duplicateIdx);
l--;
}
}
return this;
}
[
"",2,4,"A","abc",
"",2,4,"A","abc",
"",2,4,"A","abc",
"",2,4,"A","abc",
"",2,4,"A","abc",
"",2,4,"A","abc",
"",2,4,"A","abc",
"",2,4,"A","abc"
].uniq() // ["",2,4,"A","abc"]
使用ES6（一个衬垫）
基元值数组
let originalArr= ['a', 1, 'a', 2, '1'];
let uniqueArr = [...new Set(originalArr)];
对象阵列
let uniqueObjArr = [...new Map(originalObjArr.map((item) => [item["propertyName"], item])).values()];
const ObjArray = [
{
name: "Eva Devore",
character: "Evandra",
episodes: 15,
},
{
name: "Alessia Medina",
character: "Nixie",
episodes: 15,
},
{
name: "Kendall Drury",
character: "DM",
episodes: 15,
},
{
name: "Thomas Taufan",
character: "Antrius",
episodes: 14,
},
{
name: "Alessia Medina",
character: "Nixie",
episodes: 15,
},
];
let uniqueObjArray = [...new Map(ObjArray.map((item) => [item["id"], item])).values()];
